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Anit [1.1K]
3 years ago
10

By using the principle of dimensional consistency, what is the correct dimension for thermal conductivity in the SI?

Physics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

Explanation:

from Fourier law,

q = -K(∆T/L)

but q = Q/A,

hence,

K = (QL)/(AΔT)

Q = Joules/s = ML²/T³

L = L

A = L²

∆T = Kelvin = K

since K = (QL)/(AΔT)

substitute the fundamental units into the above equation we have

K = (ML²/T³)(L)/(L²K) = ML³/T³L²K = ML/T³K

the thermal conductivity, K dimensionality = ML/T³K

or mass lenght per cube unit seconds per Kelvin

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How long does a 50 kW pump motor have to run to pump 500 cubic meters of water from a 180m deep mine
Ghella [55]

Answer:

t = 17658 s = 294.3 min = 4.9 h

Explanation:

The general formula for power is:

P = \frac{W}{t}

where,

P = Power of the Motor = 50 KW = 50000 W

W = Work Done by Motor = Change in P.E of Water = mgh

g = acceleration due to gravity = 9.81 m/s²

m = mass of  water = ρV

h = depth of water = 180 m

ρ = density of water = 1000 kg/m³

V = Volume of Water = 500 m³

t = time taken = ?

Therefore,

P = \frac{mgh}{t}=\frac{\rho Vgh}{t}\\\\t = \frac{\rho Vgh}{P}\\\\t = \frac{(1000\ kg/m^3)(500\ m^3)(9.81\ m/s^2)(180\ m)}{50000\ W}\\\\

<u>t = 17658 s = 294.3 min = 4.9 h</u>

6 0
3 years ago
A boy pushes a 50 kg wheelbarrow with a velocity of 0.5 m/s. If he uses a force of 10 N, how far does he push
labwork [276]

Answer:

d=1.25 m

Explanation:

fd=.5mv2-.5mv1; 10(d)=.5(50)(.5)-0; 10(d)=12.5; d=12.5/10; d=1.25 m

4 0
3 years ago
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air
MArishka [77]

This question involves the concepts of work done, pressure, and temperature.

The work done per mol of the air is "-724.71 J/mol".

Using the given formula for work done:

W=RTln\frac{P_1}{P_2}

where,

W = work done per mol = ?

R = universal gas constant = 8.314 J/mol.k

T = absolute temperature = 30°C + 273 = 303 k

P₁ = initial pressure = 30 KPa

P₂ = final pressure = 40 KPa

Therefore,

W= (8.314\ J/mol.k)(303\ k)ln\frac{30\ KPa}{40\ KPa}\\

<u>W = -724.71 J/mol</u>

<u></u>

Learn more about pressure here:

brainly.com/question/23358029?referrer=searchResults

7 0
3 years ago
a 2.5-kg object is dropped from a height of 1000 m. what is the force of air resistance on the object when it reaches terminal v
Sergio [31]

Answer:

24.5 N

Explanation:

The falling object experiences its weight acting downwards and the air resistance in the opposite direction.

The air resistance increases with velocity so there may come a point, depending on the shape of the object and if there is sufficient height, where these 2 forces are equal.

Since the object has no net forces acting on it it will, according to Newton, no longer accelerate but continue with a constant velocity.

This is called Terminal Velocity.

So:

Air resistance = weight

R = m g

R = 2.5 × 9.8  = 24.5N

3 0
4 years ago
A block is attached to a spring and rests on a horizontal, frictionless surface. The block is pulled to the right and released f
lana66690 [7]

Answer:

Explanation:

x(t) = (3.5 cm)cos[(0.8 rad/s)t]

Angular velocity ω = .8

Time period = 2π / ω

= 2 X 3.14 / .8

= 7.85 s

First time block will pass through equilibrium is T/4 ,

Second time block will pass through equilibrium

= 3.T/4

= 3/4 x 7.85

= 5.8875 s

6 0
3 years ago
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