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Nataly [62]
3 years ago
11

Two vectors are illustrated in the coordinate plane.

Physics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer: (-4.3, 2.5)

Explanation:

In the second quadrant, magnitude of the vector is 5 and angle is 30° from the negative x-axis.

We can write this in terms of its components:

-5 cos 30^o \hat i + 5 sin 30^o\hat j

-4.3\hat i+2.5 \hat j

Thus, the components of vector in the second quadrant are (-4.3, 2.5)

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What is v^2=0.05-4.9 please i need this asap​
Margaret [11]

Answer:

v =2.02

Explanation:

v^2=0.05-4.9

v^2=-4.85

square root both side

v=2.02

^^^^this is a not a perfect square  

7 0
3 years ago
Which statement accurately describes a relationship between parts of the
sammy [17]

<u>Answer:</u>

C. There are trillions of galaxies in the universe.

<u>Explanation:</u>

A. is wrong as nebulae are found inside galaxies and inside the universe, not inside stars.

B. is wrong because there are trillions of galaxies in the universe, not the latter.

D. The solar system consists of the eight planets, the Sun, comets, meteors, dwarf planets, and is inside the Milky Way galaxy and thus cannot have galaxies inside it.

<em>Please give Brainliest</em>

8 0
3 years ago
Read 2 more answers
To clean the outside of your house you rent a small high-pressure water sprayer. The sprayer’s pump delivers slow-moving water a
Zigmanuir [339]

Answer:

Velocity is 134.16 m/s

Explanation:

Slow moving water pressure is the dynamic pressure. Dynamic pressure is actually the kinetic energy per unit volume of a fluid particle. It is equal to the difference between stagnation pressure and static pressure and also can be derived from Bernoulli's equation.

Formula for Dynamic Pressure (P) is

               P = 0.5 d v²

Where d is density of fluid and v is the velocity.

Density of water = 1000 kg/m³

P = 9000000 Pa

V = ?

                      P = 0.5 d v²  

         9000000 = 0.5 × 1000 × v²

                       v = √(9000000 ÷ 500)

                       v = 134.16 m/s

5 0
3 years ago
A person shouting at the top of his lungs emits aboue 1.0 w of energy as sound waves. What is the sound intensity 1.0 m from suc
umka21 [38]

Answer:

I=0.0795\ W/m^2

Explanation:

When a person shouts it emits 1 W of energy as sound waves, P = 1 W

Let I is the sound intensity 1 meters from such a person. We know that the power per unit area is called the sound intensity of the person. Its formula is given by :

I=\dfrac{P}{A}

I=\dfrac{P}{4\pi r^2}

I=\dfrac{1\ W}{4\pi (1\ m)^2}  

I=0.0795\ W/m^2

So, the sound intensity of such a person is 0.0795\ W/m^2. Hence, this is the required solution.

3 0
4 years ago
A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.
zalisa [80]

Answer:

P_{f} =(5.7 x 10^{7 i - 2.24 x 10^{7 j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

F= \frac{Gm_{1}m_{2} }{r^{2} } r^

Plugging in the values, we have

F= [(6.67x10^{-11})(1500)(5.97 x 10^{24})(8x10^{6}i + 9x10^{6 j)] / ((8x10^{6})² + (9x10^{6 )²)^{1.5}

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

P_{f} = P_{i + FΔt

P_{f} = 1500(3.5 x 10^{4 i - 1.8x10^{4 j) + (2736i + 3078j)(1.5x10^{3)

P_{f} =(5.7 x 10^{7  i- 2.24 x 10^{7 j)kgm/s

4 0
4 years ago
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