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NISA [10]
3 years ago
13

Very easy answer but does any one know what C is

Mathematics
2 answers:
Pavel [41]3 years ago
7 0
Answer: As the number of rides given by the taxi driver increased, the earnings of the taxi driver also increases.
IgorLugansk [536]3 years ago
5 0

Answer:

Step-by-step explanation:

they want you to recognize that it's a linear relationship

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Could a triangle be constructed with side lengths 4 cm, 5 cm and 13 cm? *​
Ratling [72]

Answer:

NO.

Step-by-step explanation:

No because 13 > 4 + 5.

7 0
3 years ago
Eric practiced piano and guitar for a total of 8 hours this week. He practiced the piano for 1/4 of that time. How many hours di
Oduvanchick [21]

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Step-by-step explanation:

I said idk

5 0
3 years ago
Pleaseeeeee helpppppppp i will mark brainlest
OlgaM077 [116]

Answer:

b

Step-by-step explanation:

The sum of angles in a triangle is 180°. Therefore,

x - 11 + 48 + 90 = 180

x + 127 = 180

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8 0
3 years ago
Read 2 more answers
What is the mass (in grams) of 8.11×1026 CO2 molecules?
Kobotan [32]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>5</u><u>9</u><u>,</u><u>2</u><u>7</u><u>5</u><u>.</u><u>7</u><u>4</u><u> </u><u>grams</u>

Step-by-step explanation:

• Molecular mass of carbon dioxide

= (12 \times 1) + (16 \times 2) \\  = 12 + 32 \\  = 44 \: g

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

{ \sf{6.02 \times  {10}^{23}  \: molecules = 44 \: g }}\\  { \sf{8.11 \times  {10}^{26}  \: molecules =( \frac{8.11 \times  {10}^{26} }{6.02 \times  {10}^{23} }   \times 44) \: g}} \\  \\  = { \boxed{ \boxed{ \bf{59275.7 \:  \: g}}}}

6 0
3 years ago
Please help, I am super stuck and I cant lose points<br><br> this homework is 16 points total
bekas [8.4K]
Hello,

7)  A∪C={1,2,3,4,5,7,9}

8) A∩B={2,4}

C'= complement of C ={2,4,6}

9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}

10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}

Are you blind?
4 0
3 years ago
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