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NARA [144]
4 years ago
7

Jerry's strips of dry meat joint sells of these two types of dry meat. he sells twice as many bags of dried beef as he does bags

of dried turkey . His profit from the dryed beef is a 1.50 per bag while his profit for dryed turkey is a $2 per bag how many bags of each must he sell to profit for $ 500. please help
Mathematics
1 answer:
igomit [66]4 years ago
3 0
Assume Jerry sells x bags of dried turkey, and 2x bags of dried beef. He profits ($2)x on dried turkey, and ($1.5)(2x) on the dried beef. Therefore, his total profit is 2x + 3x = 5x. Since this is equivalent to $500, we can solve
5x = 500
x = 100
Therefore, Jerry must sell 100 bags of dried turkey and 200 bags of dried beef.
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8 0
3 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
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the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
3 years ago
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