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beks73 [17]
3 years ago
15

What direction for negative and positive go in​

Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer:

negative=left positive=right

Step-by-step explanation:

negatives are less than positives

slega [8]3 years ago
4 0

Answer:

  opposite directions

Step-by-step explanation:

Conventionally, positive is to the right or up. The actual direction depends on the desired coordinate system, and may vary from one context to another.

In spherical coordinates, positive distance measure is away from center. Positive angles of one sort are CCW from the "x direction" as seen from the "north pole" (z-direction), and positive angles of the other sort are away from the axis pointing to the "north pole."

In mechanics, reference points and directions are often chosen to simplify the problem as much as possible. The point of application of an unknown force, for example, may be chosen as a reference point simply so its moment about that point is zero and can be ignored.

___

In navigation on the Earth's surface, bearing angles are generally positive measured clockwise from North. In Algebra, angles are usually positive measured counterclockwise from the +x axis (East on a map conventionally oriented).

___

In conventional 2-dimensional algebra problem coordinates, positive x is to the right, and positive y is up. Angles are positive counterclockwise from the +x axis and negative clockwise from that axis. However, you can define reference points and positive directions any way you like, as long as you make your coordinate system known to anyone interested in your work. Generally, negative coordinates are in the direction opposite positive ones.

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A rectangular prism has a base area 56 ft.² and a volume of 840 ft.³ the length of the base is longer than the width if the sum
suter [353]

Answer:

The length of the base in feet is 8 ft.

Step-by-step explanation:

The volume V of the rectangular prism is given by

V = l × w × h

But Area, A = l × w

∴ V = A × h

Where A is the base area and h is the height

From the question

A = 56 ft.²  and V = 840 ft.³

∴ 840 ft.³ = 56 ft.² × h

840 ft.³ / 56 ft.² = h

15 ft. = h

∴ h = 15 ft.

Hence, the height of the rectangular prism is 15 ft.

Also, from the question

the sum of the length and the width of the base is equal to the height

i.e l + w = h

where l is the length of the base and w is the width of the base

Then, l + w = 15 ------ (1)

Also, A = l × w

Then, 56 = l × w ------- (2)

From equation (1)

l + w = 15

Then, w = 15 - l ------- (3)

Substitute this into equation (2)

56 = l × w

56 = l × (15-l)

56 = 15l - l²

Then,

l²- 15l + 56 = 0

l² -8l -7l + 56 = 0

l(l - 8) -7(l - 8) = 0

(l - 7)(l - 8) = 0

l - 7 = 0 OR l - 8 = 0

∴ l = 7 OR l = 8

Substitute the values of l into equation (3)

w = 15 - l

when l = 7

w = 15 - 7

w = 8

and when l = 8

w = 15 - 8

w = 7

From the question, the length of the base is longer than the width

∴ l = 8 and w = 7

Hence, the length of the base in feet is 8 ft.

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Answer:

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Step-by-step explanation:

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