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goldenfox [79]
3 years ago
15

Every evening jenna empties her pockets and puts the change in a jar at the end of the week she had 38 coins all of them dimes a

nd quarters when she added them up she had a totals of $6.95
Mathematics
2 answers:
ser-zykov [4K]3 years ago
8 0
I imagine the part you left out was "how many of each coin did she have?".  I'm going with that.  The thing is you have to relate the NUMBER of coins to each other, which is very different from the VALUE of the coins.  I could have 1 single quarter, but it's worth 25 cents.  Number vs. value.  If she had 38 coins made up of dimes and quarters, then d + q = 38.  That's the number of dimes and quarters, both still unknown.  A dime is worth .10 and a quarter is .25.  Therefore, .10d + .25q = 6.95.  That's the value of the coins.  Solve the first equation for dimes.  d = 38 - q.  Now we can sub in that value of d into the second equation, so we have only one unknown instead of 2.  .10(38-q)+.25q=6.95.  Distribute through the parenthesis to get 3.8-.1q+.25q=6.95.  Combine all the like terms on both sides to get.15q=3.15.  Solve for q and get that q = 21.  So we have 21 quarters.  38-21 = # of dimes, which is 17.  There you go!  Hope that's what you actually needed!  ;)
dedylja [7]3 years ago
7 0
A) d + q = 38
B)  .1d +.25q = 6.95
Multiply A) by -.1
A) -.1d + -.1q = -3.8The adding B)B)  .1d +.25q = 6.95
.15q = 3.15
21 quarters17 dime
Double-Check********************************************************
17 * .10 + 21 * .25 = 
1.70 + 5.25 = 
6.95

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There are 50 deer in a particular
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answered

There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents

the number of deer y in that forest after x months? Round to the nearest thousandth.

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dribeiro

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Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

y(x) = 50*(1.013)^x

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2 years ago
Mr. Lawrence used 100 tiles when he put a new floor in the kitchen 34 tiles are squares and 16 tiles are rectangles write the to
Oliga [24]
<h3>Fraction of square tiles  = (\frac{4}{25})   = 0.16</h3><h3>Fraction of rectangle tiles  = (\frac{17}{50})   = 0.34</h3>

Step-by-step explanation:

Total number of tiles to be used in the kitchen = 100

The total number of square tiles  = 34

The total number of rectangle tiles  =  16

Now, calculating the total fraction of square tiles:

The fraction of square tiles  = \frac{\textrm{Total number of square tiles}}{\textrm{Total number of tiles}}  = \frac{16}{100}   = \frac{4}{25}

Also, solving the fraction, we get \frac{4}{25}  = 0.16

So, the decimal value of square tiles  = 0.6

Calculating the total fraction of rectangle tiles:

The fraction of rectangle tiles  = \frac{\textrm{Total number of rectangle tiles}}{\textrm{Total number of tiles}}  = \frac{34}{100}   = \frac{17}{50}

Also, solving the fraction, we get \frac{17}{50}  = 0.34

So, the decimal value of rectangle tiles  = 0.34

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