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MrMuchimi
3 years ago
9

Please help on this 2 questions I have

Mathematics
1 answer:
Nataly [62]3 years ago
7 0
The left one is 4 and the right one is 10. 2(4)+5=13 and 1+2(10)=21
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How do you find the parameterization of a helix?
Marina CMI [18]

Answer:

\left\{\begin{array}{l}x=r\cos t\\ \\ y=r\sin t\\ \\z=at\end{array}\right.

Step-by-step explanation:

A <u>helix</u> is a curve for which the tangent makes a constant angle with a fixed line. The shortest path between two points on a cylinder (one not directly above the other) is a fractional turn of a helix, as can be seen by cutting the cylinder along one of its sides, flattening it out, and noting that a straight line connecting the points becomes helical upon re-wrapping (see attached diagram for helix).

The parametrization for the helix is

\left\{\begin{array}{l}x=r\cos t\\ \\ y=r\sin t\\ \\z=at\end{array}\right.,

where r is the radius of the helix, a is the constant, and t\in [0,2\pi ) is the parameter

7 0
3 years ago
Y = 5x+p point (-2, 1) p=?
ivann1987 [24]
The value of p = 11

y = 5x + p
1 = 5(-2) + p
1 = -10 + p
11 = p
6 0
3 years ago
Use the model to complete the number sentence 1/2
VladimirAG [237]
That is one half also 1/2 if this was not what u where looking for then just tell me

8 0
3 years ago
Find the upper bound for 96.3cm measured to the nearest tenth of a cm
Zarrin [17]

Answer:

100cm

Step-by-step explanation:

Will be 100cm as when approximated to tenth

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8 0
3 years ago
Find the linearization L(x) of the function at a. f(x) = x^4 + 2x^2, a = 1
gregori [183]

The equation of the tangent line at x=1 can be written in point-slope form as

... L(x) = f'(1)(x -1) +f(1)

The derivative is ...

... f'(x) = 4x^3 +4x

so the slope of the tangent line is f'(1) = 4+4 = 8.

The value of the function at x=1 is

... f(1) = 1^4 +2·1^2 = 3

So, your linearization is ...

... L(x) = 8(x -1) +3

or

... L(x) = 8x -5

8 0
3 years ago
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