$\frac{2}{3}(5*4):3+ \frac{6}{7} = \\ \\ \frac{2}{3}*20:3+ \frac{6}{7} = \\ \\ \frac{40}{3}:3+ \frac{6}{7} = \\ \\\frac{40}{9}+ \frac{6}{7}= \\ \\ \frac{40*7+6*9}{7*9}= \\ \\\frac{280+54}{63}= \\ \\ \frac{334}{63} = \\ \\ 5 \frac{19}{63} \ \ \ [as \ a \ mixed \ fraction] \\ \\ \approx 5.3 \ \ \ [as \ a \ decimal\ fraction \ to \ the \ nearest \ tenth]$

8 0

3 years ago

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#11 (Angles with Equations) In the figure below, 2POR is 180°.

lina2011 [118]

Answer:

Step-by-step explanation:

The three angles form a straight line, so they add to 180.

x + x + 70 = 180

Combine like terms

2x+70 =180

Subtract 70 from each side

2x+70-70 =180-70

2x= 110

Divide by 2

x = 55

SQT = x

So SQT = 55

4 0

3 years ago

Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste

olga_2 [115]

1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)= $(x-a)^{3}$

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

$f(x)=b(x-a)^{3}$

4. Now, f(0)=-5 so $-5=f(0)=b(0-a)^{3}=b(-a) ^{3}=-ba ^{3}$

$-5=-ba ^{3}$

$5=ba ^{3}$

$b= \frac{5}{ a^{3} }$

5. the function is $f(x)=\frac{5}{ a^{3} }(x-a)^{3}$ where a can be any real number except 0

7 0

3 years ago

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