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Genrish500 [490]
3 years ago
5

PLEASE HELP!

Mathematics
1 answer:
MrRa [10]3 years ago
3 0
If Bryce does the arithmetic in the way usually taught, his partial products will be
.. 410 * 264 = 0*264 +10*264 +400*264
.. = 0 +2640 +105,600 . . . . . . . . . . . . . . . . . matches selection C

_____
Bryce could do the math using Vedic methods to get
.. 80,000 + (24+2)*1000 +(2*0 +6*1 +4*4)*100 +(6*0+4*1)*10
.. = 80,000 +26,000 +2,200 +40
.. = 108240
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Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the
stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

First term: a = -15

Common difference is

d = -33-(-15)

d = -33+15

d = -18

Now, nth term  of an arithmetic sequence is

a_n=a+(n-1)d

Substitute a=-15 and d=-18.

a_n=-15+(n-1)(-18)

a_n=-15-18n+18

a_n=-18n+3

Therefore, the nth term of the given arithmetic sequence is a_n=-18n+3.

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