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Andrei [34K]
3 years ago
12

When Emilio was at the park today, he saw four kites. This is two less than 3 times the number of kites he saw yesterday. Let y

equal the number of kites Emilio saw yesterday.
A. 3y - 2 = 4
B. 2 - 3y = 4
C. 2y - 3 = 4
D. 4 - 2 = 3y
Mathematics
1 answer:
dsp733 years ago
4 0

Answer: the correct answer is a

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Rephrase in contrapositive form:
miv72 [106K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

The rule for Contrapositive is: Negative both statements and interchange them. \sim q \rightarrow \sim p

Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.

Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".

It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".

Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.

Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.

Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"

The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

Contrapositive: If xy < 0 then x<0 and y<0.

8 0
3 years ago
12/39 in simplest form is 4/13 what are two ways to get there
arlik [135]
Divide 3 on the numerator and denominator.

Hoped this helped.

~Bob Ross®
7 0
3 years ago
Read 2 more answers
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
Finding interior angles of triangles<br>​
AnnZ [28]

Answer:

A triangle is 180 degrees. Imagine that two angles would be given as maybe 89 and 30 degrees. With these two angles already given you can find the last third angle by adding the 2 given angles and subtracting it from 180. There fore it would look like 180-119=61. 61 would be your unknown angle degree.

<u>If you meant something else please comment I will help you more.</u>

7 0
3 years ago
A rectangle has a length the area of the rectangle is 180(2w-9=180).Find the length and the width of the rectangle. Find the per
djverab [1.8K]
<span>A rectangle has a length the area of the rectangle is 180(2w-9=180).Find the length and the width of the rectangle. Find the perimeter of the rectangle</span>
5 0
3 years ago
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