So u would take 5 add 6 freee points dont mind if i dooo
Answer:
762 days
Step-by-step explanation:
Given

Let the rate be R.
So the rate change with time is represented as:

So:

To get the number of insects between day 0 and day 3, we need to integrate dR and set the bounds to 0 and 3
i.e.
becomes


Integrate
![R = 200t + \frac{10t^2}{2} + \frac{13t^3}{3} [3,0]](https://tex.z-dn.net/?f=R%20%3D%20200t%20%2B%20%5Cfrac%7B10t%5E2%7D%7B2%7D%20%2B%20%5Cfrac%7B13t%5E3%7D%7B3%7D%20%5B3%2C0%5D)
Solve for R by substituting 0 and 3 for t





<em>The population of insect between the required interval is 762</em>
Given:
x² + 11x + 121 = x + 96
First, we need to convert it into a quadratic equation.
x² + 11x - x + 121 - 96 = 0
x² + 10x + 25 = 0
a = 1 ; b = 10 ; c = 25
Quadratic formula:
x = (-b <u>+</u> (√b² - 4ac)) ÷ 2a
The discriminant is under the radical sign
discriminant ⇒ b² - 4ac ⇒ 10² - 4(1)(25) ⇒ 100 - 100 = 0
Correct answer is A. 0
Answer:
mesure of b is what hahhahaha
Don't you have to multiply the Area's ?