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3 years ago

What is the area of the shaded region? (Use 3.14 for Pi) *

Mathematics

1 answer:

love history [14]3 years ago

8 0

Answer:

The area of the shaded region is the difference between the areas of the rectangle and the square.

Step-by-step explanation:

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A company is making building blocks. Each building block is a cube and has volume 125/729 ft cubed . How long is each side of th

MariettaO [177]

Answer: The length of each side of the building block is 0.56 feet

Step-by-step explanation:

A company is making building blocks. Each building block is a cube and has volume 125/729 ft cubed . Each of the building blocks has 6 faces which are squares, 8 vertices and 12 edges.

Since a square has all sides to be equal sides,

The volume of the cube = the volume of the building block =

Product of length,L, width, W and height, H.

Volume of the building block = L × W × H

Since length = width = height,

Volume of cube = L^3

From the information given,

Volume of a building block = 125/729ft cubed

L^3 = 125 / 729

Taking cube root of both sides of the equation,

L = cube root of 125/729

L = 5/9

= 0.56 feet

4 0

3 years ago

Solve the equation for y (y-3)^2=4y-12

Ket [755]

(y -3)^2 = 4y - 12

Expand.

(y-3)(y -3) = 4y - 12

y² - 6y + 9 = 4y - 12

y² - 6y -4y + 9 + 12 = 0

y² - 10y + 21 = 0

Factors are -7y and - 3y

y² - 10y + 21 = 0

y² - 3y - 7y + 21 = 0

y(y - 3) -7(y - 3) = 0

(y - 3)(y - 7) = 0

y-3 = 0 or y - 7 = 0

y = 0 + 3 or y = 0 + 7

y = 3 or 7

8 0

3 years ago

What are the first 4 terms of the arithmetic sequence in the

KengaRu [80]

the first 4 sets of coordinates are (2,1) (3,5) (4,9) and (5,13)

7 0

3 years ago

which linear system has been correctly solved for one of the variables from the following system? 2x - y = -1 2x y = -7 2x - y =

mr Goodwill [35]

If you would like to solve the system of linear equations, you can do this using the following steps:

2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x

The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>

4 0

3 years ago

What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4

Alecsey [184]

Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: $f(x)=\dfrac{3x^2}{x^2-4}$

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. $x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2$

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at $y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}$

i.e. $y=\dfrac{3}{1}=3$

Hence, f(x) will have horizontal asymptote at y=3.

3 0

3 years ago