Mostly any bug you can think of
Answer:
The mentioned case is an illustration of the missense mutation. A missense mutation is a kind of nonsynonymous substitution, that is, it is a mutation in which a variation in a solitary nucleotide leads to the formation of a codon, which encrypts for a distinct kind of amino acid.
When a missense mutation takes place within a DNA, a modification in one of the RNA codon sequences results at the time of transcription. This change in codon will ultimately result in the formation of a different amino acid, which gets presented within a protein at the time of translation. Like in the given case, a change in codon resulted in the substitution of the amino acid tyrosine with an amino acid cysteine.
Answer:
The haploid structure of the plant, during a stage in plant's life cycle, is known as the <u>gametophyte.</u>
Explanation:
The life cycle of plants includes a haploid generation and a diploid generation. Both the structures are multicellular.
The diploid structure of a plant is known as sporophyte. This structure produces spores via meiotic division.
Whereas, the haploid structure of the plant, known as the gametophyte, is formed from spore and produces haploid gametes.
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
