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Veronika [31]
3 years ago
13

Here is a list of numbers.

Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

15

Step-by-step explanation:

12 13 14 15 17 19 22

you need to arrange the numbers in order from the smallest value to the largest

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In the jone school library,10/20 of the computers have scanners.in simplest form, which fraction of the computers have scanners?
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1/2

Step-by-step explanation:

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3. Solve to determine the unknown variable in the
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A triangle has side lengths of 24 in., 32 in., and 40 in. Is the triangle acute, obtuse, or right? A) right. B) obtuse. C) acute
statuscvo [17]
The answer is:  [A]:  "right [triangle]" .
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Explanation:
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Given:  Side lengths:
________________________________________________
  " <span>24 in., 32 in., and 40 in " ;  
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Divide each side length by "8" ; 
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24 in. / 8 = 3 in. ; 

32 in. / 8 = 4 in. ;  and
 
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3 in . , 4, in,  5 in. ;  is a "right triangle" ; 

since:  3</span>² + 4² = 5² ;

→  9 + 16 = 25 ; 

according to the Pythagorean theorem:  " a² + b² = c² " .
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8 0
3 years ago
A chemical company makes two brands of antifreeze. The first brand is 30% pure antifreeze and the second brand is 55% pure antif
Phantasy [73]

Answer:

  • 64 gallons 30%
  • 96 gallons 55%

Step-by-step explanation:

The amount of each brand can be found by writing and solving an equation that makes use of the given relations.

<h3>Setup</h3>

Let x represent the quantity of 55% pure antifreeze needed in the mixture. Then the quantity of the 30% brand is (160-x). The amount of pure antifreeze in the mixture is ...

  0.55x +0.30(160 -x) = 0.45(160)

<h3>Solution</h3>

Subtracting 0.30(160), we have ...

  x(0.55 -0.30) = 160(0.45 -0.30)

  x = 24/0.25 = 96 . . . . . simplify, divide by the coefficient of x

96 gallons of the 55% brand, and 64 gallons of the 30% brand must be used.

__

Read more about mixture problems here:

brainly.com/question/26751698

4 0
2 years ago
What is a solution set
umka21 [38]
<span>the set of all the solutions of an equation or condition.



</span>
7 0
3 years ago
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