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deff fn [24]
3 years ago
9

The volume of a cylinder with base radius 3 cm and height 6 cm is

Mathematics
1 answer:
Brut [27]3 years ago
8 0

Answer:

<u>54</u> π cubic centimeters

Step-by-step explanation:

Formula for the volume of a cylinder: πr²h

π×3²×6=

9×6×π=

54π cm³

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In a national survey of 1987 adults, 1570 responded that lack of respect and courtesy in American society is a serious problem,
Alik [6]
<h2>Answer with explanation:</h2>

As per given , we  have

H_0: p\leq\dfrac{3}{4}\\\\H_a: p>\dfrac{3}{4}

Since , alternative hypothesis is right tailed, so the test is a right tailed test.

n= 1987

Proportion of adults believe that rudeness is a worsening problem : p=\dfrac{1257}{1987}\approx 0.6326

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{ 0.6326-0.75}{\sqrt{\dfrac{0.75(1-0.75)}{1987}}}=-12.09

(since , the normal curve takes values of z from -7 to 7, so we use critical value to draw conclusion.)

The critical value for a significance level of 0.005= 1.645

Since , absolute test statistic value (12.09) is greater than the critical value (1.645), it means there is statistical significance and so we reject the null hypothesis.

3 0
3 years ago
Solve for y. 2/3 + y - 4/5 = 1/3 Enter your answer in the box. y =
erica [24]
<span>2/3 + y - 4/5 = 1/3
         y = 1/3 - 2/3 + 4/5
         y = -1/3 + 4/5
         y =-5/15 + 12/15
         y = 7/15</span>
3 0
2 years ago
Read 2 more answers
Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a
Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.65, n = 153. So

\mu = E(X) = 153*0.65 = 99.45

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.65*0.35} = 5.9

Consider the probability that greater than 94 out of 153 people will not get the flu this winter

This probability is 1 subtracted by the pvalue of Z when X = 94. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 99.45}{5.9}

Z = -0.92

Z = -0.92 has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

7 0
3 years ago
a group of students surveyed chose baseballand soccer as there favorite sport in th ratio 3:8 if 132 students were surveyed , fi
makkiz [27]

132/11= 12

12 times 8 = 96

96 students chose soccer.

8 0
3 years ago
How do u solve X^3y divided by Y^4x
julia-pushkina [17]
All I can say to help you with this, is to rewrite the division as a fraction,
x^3y / y^4x

Sorry, if it's not much help.
5 0
3 years ago
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