Find the area of the crescent-shaped region (called a lune) bounded by arcs of circles with radii r = 2 and r = 14
1 answer:
the complete question in the attached figure
Let
A1-------> half of the area of the blue circle
A2-------> area of the circular segment formed by the diameter of the blue circle treated as a chord of the red circle
A3---------- > area of the crescent-shaped region
A3=A1-A2A1=pi*2²/2=6.28
Area of the circular sector
if 360 º corresponds to an area of pi*14²
2*arc sin(2/14)------------------- X
X=16.43*pi*14²/360---------- > X=28.10
Triangle area:
------- >(4/2)*√(14²-2²=27.72
Area of the circular segment A2=Area of the circular sector-Triangle area
A2=28.10-27.72=0.38
A3= A1-A2=6.28-0.38=5.90 units²
the answer is 5.90 units²
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4 triangles with the base b = 5ft and the height h = 6ft
4 rectangles with the lenght l = 5ft and the width w = 4ft
1 square with side a = 5ft.
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The formula of an area of a rectangle:
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The formula of an area of a square:
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The Surface Area of composite solid:
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The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.
The explicit formular for the geometric sequence is shown as;
The explicit formula is shown as;
54 x (0.750)^9
The rest is simply to solve for the height on the 10th bounce