Find the area of the crescent-shaped region (called a lune) bounded by arcs of circles with radii r = 2 and r = 14
1 answer:
the complete question in the attached figure
Let
A1-------> half of the area of the blue circle
A2-------> area of the circular segment formed by the diameter of the blue circle treated as a chord of the red circle
A3---------- > area of the crescent-shaped region
A3=A1-A2A1=pi*2²/2=6.28
Area of the circular sector
if 360 º corresponds to an area of pi*14²
2*arc sin(2/14)------------------- X
X=16.43*pi*14²/360---------- > X=28.10
Triangle area:
------- >(4/2)*√(14²-2²=27.72
Area of the circular segment A2=Area of the circular sector-Triangle area
A2=28.10-27.72=0.38
A3= A1-A2=6.28-0.38=5.90 units²
the answer is 5.90 units²
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Answer:
The beam will bend by 50 mm with a mass of 100kg?
Step-by-step explanation:
The first step in solving the problem of direct variation is setting up the relation mathematically.
We can do this as follows:
The bending of the beam varies directly as its mass.
here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k
k = 20 /40 = 0.5
We can now use this to find the distance the beam will bend with a mass of 100kg?
This will be
There fore, the beam will bend by 50 mm with a mass of 100kg?