we have
Min=26
Q1=67
Q2=80
Q3=87
Max=100
Mean=76
Mode=100
standard deviation=76
IQR=20
so
In this problem
the mean is equal to the standard deviation
therefore
<h2>The standard deviation is incorrectly</h2>
Option A. is correct for the given condition.
Lets solve it through steps of range and functions,
First of all, Solve the equation:
(1)
(2)
So these would be the ranges of X in between 5 and -5.
Hence option A. 
is correct.
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Outer Square perimeter minus inside perimeter equals outside square perimeter
The value of x when y =4 is 2
<h3>How to solve for x?</h3>
An inverse proportion is represented as:
k = yx
Where
k represents the constant of proportion
When y = 2, x = 4.
So, we have:
k =2 * 4
k = 8
Substitute k = 8 in k = yx
So, we have:
yx = 8
When y = 4, we have:
4x = 8
Divide by 4
x = 2
Hence, the value of x when y =4 is 2
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