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DiKsa [7]
3 years ago
12

I don’t know what to do

Mathematics
2 answers:
barxatty [35]3 years ago
8 0
12.60 because 20% of 15 is 3 subtract 3 from 15 it is 12 and 5% of 12 is .60




sergey [27]3 years ago
4 0
20% of 15 is 12$, and tax is 5% so it comes out to 12.60$
The answer is B
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What is the missing number in the table?
mariarad [96]

Answer:

1296

Step-by-step explanation:

the y is multiplying by six each time 6*6 = 36

36*6 = 216

216*6 = 1296

2196 = 7776

4 0
3 years ago
What is the measure of angle B in degrees?<br> A) 30<br> B) 45<br> C) 60<br> D) 90
Triss [41]

Answer:

its a 30 my friend and if its not a then choose b hope this helped

Step-by-step explanation:

5 0
2 years ago
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 &lt; 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
2 years ago
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Aleks04 [339]

Answer:

Step-by-step explanation:

D

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area of D=1/2 *6*6=18

so  D

6 0
2 years ago
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natka813 [3]

Answer:

7

Step-by-step explanation:

When evaluating absolute values, a great way to remember what they do is simple. No matter the number, whether it is negative or positive, the number(s) IN THE absolute values are ALWAYS positive.

So, |x + y| is then substituted with the numbers given for the variables.

|x + y|

|8 - 15|

|-7|

7

Hope this helps!

3 0
2 years ago
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