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3 years ago

Are the linear equations in standard form? sort each equation into the appropriate category.

1 answer:

4 0

What equation? You would have to pass a photo, but...
Standard form is: ax+by=c
Slope intercept form is: y=my+b
Point slope for is: y − y1 = m(x − x1)

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Venn diagrams: unions, intersections, and complements Attached is the photo references

ohaa [14]

Answer:

4, 8

Step-by-step explanation:

D iswholly part of B. so B intersect D is D

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2 years ago

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Mean of the integers 8,-11,18,-8,-3

g100num [7]

Answer:0.8, just add up and find the mean

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3 years ago

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6th grade math help me pleaseeee

Helga [31]

Answer:

First one.

Step-by-step explanation:

0.3/3=0.1 ==> 0.1$ per meter

0.77/7 ==> 0.11$ per meter

The first option is cheaper, therefore better to buy if you agree with "the cheaper. the better".

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2 years ago

PLEASE HELP MEEE ASAP

lys-0071 [83]

Step-by-step explanation:

first of all, g(x) has only negative functional result values (y) except for 0.

and a square is always positive.

so, the only possible right answers are the ones that include a minus ("-") sign.

the graph shows us that g(x) goes through the points (1, -3) and (-1, -3).

so, which equation turns an x = 1 into an y = -3 ?

therefore, the right answer must be D.

g(x) = -3x²

it works for both points :

-3 = -3×1² = -3 correct

-3 = -3×(-1)² = -3×1 = -3 correct

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3 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.

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1 year ago

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