2x+y+3=0
...................
Answer:
see below
Step-by-step explanation:
Each segment in ΔA"B"C" is 3 times the length of the corresponding segment in ΔABC. This is due to the dilation by a scale factor of 3.
Then you have ...
![\overline{A''B''}=3\overline{AB}\quad\text{or}\\\\\dfrac{\overline{AB}}{\overline{A''B''}}=\dfrac{1}{3}](https://tex.z-dn.net/?f=%5Coverline%7BA%27%27B%27%27%7D%3D3%5Coverline%7BAB%7D%5Cquad%5Ctext%7Bor%7D%5C%5C%5C%5C%5Cdfrac%7B%5Coverline%7BAB%7D%7D%7B%5Coverline%7BA%27%27B%27%27%7D%7D%3D%5Cdfrac%7B1%7D%7B3%7D)
The latter relation matches the second choice.
Answer:
Veronika's weight = 92 pounds
Kate's weight = 46 pounds
Step-by-step explanation:
Let Veronika's weight = x
Let Kate's weight = y
The sum of Veronika's and Kate's weight is 118 pounds.
x + y = 118
Veronika weighs 26 pounds more than Kate.
x = y + 26
How much do they weigh individually?
We substitute y + 26 for x in Equation 1
x + y = 118
y + 26 + y = 118
26 + 2y = 118
2y = 118 - 26
2y = 92
y = 92/2
y = 46 pounds
x = y + 26
x = 46 + 26
x = 92 pounds
Hence,
Veronika's weight = 92 pounds
Kate's weight = 46 pounds
Answer:
∠ 5 = 49°, ∠ 6 = 131°
Step-by-step explanation:
∠ 5 and 49° are corresponding angles and are congruent, then
∠ 5 = 49°
∠ 5 and ∠ 6 are adjacent angles and are supplementary, sum to 180° , that is
∠ 6 + ∠ 5 = 180°
∠ 6 + 49° = 180° ( subtract 49° from both sides )
∠ 6 = 131°