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Leona [35]
3 years ago
8

Jim has only dimes and nickels in his coin bank. He has 37 coins with a total value of $2.65. How many nickels are in Jim's coin

bank
Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0

Answer:

21\ nickels

Step-by-step explanation:

we know that

1\ nickel= \$0.05

1\ dime= \$0.10

Let

x-------> the number of nickels

y-------> the number of dimes

x+y=37 ------> isolate the variable y

y=37-x -------->  equation A

0.05x+0.10y=2.65 ------> multiply by 100 both sides

5x+10y=265 -------> equation B

Substitute equation A in equation B and solve for x

5x+10(37-x)=265

5x+370-10x=265

10x-5x=370-265

5x=105

x=21\ nickels

Galina-37 [17]3 years ago
7 0

Answer: the answer is 21 nickels.


Step-by-step explanation:

he only had 37 coins so if you think he has 53 nickels then you probably deserve to fail this quiz.

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Vlada [557]
<span>An upper quartile is the range of numbers above the median in a set. Thus, the numbers have to be rearranged mentally or on paper. Fortunately, there are an odd set of numbers, so one number, 25, is the median. The upper quartile is 30, 35, 40, 45.</span>
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3 years ago
Given right triangle ABCABC with altitude \overline{BD}
Alex

Answer:

x = 2\sqrt{11}

Step-by-step explanation:

AD = 4

AC = 11

DC = 11 - 4 = 7

First, find BD using the right triangle altitude theorem:

BD = \sqrt{AD*DC}

Plug in the values

BD = \sqrt{4*7}

BD = 2\sqrt{7}

Use pythagorean theorem to find x:

x² = AD² + BD²

Plug in the values

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 16 + (4*7)

x^2 = 16 + 28

x^2 = 44

Take the square root of both sides

\sqrt{x^2} = \sqrt{44}

x = \sqrt{44}

x = \sqrt{4 * 11}

x = 2\sqrt{11}

6 0
3 years ago
Read 2 more answers
Susan is writing a linear equation for the cost of her cell phone plan. In the first month, she talks for 52 minutes and is char
Alex787 [66]
Assuming that the cost per minute is the same for both months and the plan fee is the same, you can use y=mx+b for this

y is the cost of the phone plan, x is the cost per minute and b is the start cost.

so    19.41=25x+b for the first month
and  45.65=380x+b for the second month

solve both for b you get:
19.41-25x=b and 45.65-380x=b.  from this we get
19.41-25x=45.65-380x

solve for x

328x=26.24 and x=0.08

this means the cost per minute is 0.08c/min (answer A)

rewrite the equation to calculate b, and where this time, the x is the number of minutes talked.

y=0.08x+b and plug in one of the two months

45.65=0.08 * 380 + b

Solve for b and b is 15.25

so the final equation is

y=0.08x+15.25  (answer B)
5 0
3 years ago
GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?
loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

so

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

2n-1=14

solve for n

2n=14+1

2n=15

n=7.5\ cm

step 2

Find the length of GJ

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

so

GJ=\frac{1}{2}DE

we have

GE=2n+1=2(7.5)+1=16\ cm

substitute

GJ=\frac{1}{2}16=8\ cm

step 3

Find the length of HK

we have that

HK=\frac{1}{2}GJ ----> by the midpoint theorem

we have

GJ=8\ cm

substitute

HK=\frac{1}{2}8=4\ cm

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