Answer:
A= 18
Step-by-step explanation:
To find the height, find the blocks inside the shape that is completely attached (they have to be in a straight vertical line). In this case, you can see that three vertical blocks in the middle of the shape is completely attached. That means your height is 3.
To find the width, look at the how many horizontal boxes make up the top. 6 block inside the shape corispond with 6 blocks on top of the shape, so the width is six.
Multiply 6 by 3 to get 18.
You have the right idea but the endpoint is at the wrong location. Instead, the green dot should go at -1. The shading is to the right. We use a closed filled in circle here (instead of an open hole) to tell the reader "include the endpoint". So -1 is part of the solution set.
In short, the graph consists of a closed filled in circle at -1 with shading to the right. This visually describes all values that are larger than -1, or equal to -1.
A bakers dozen is 12 which would be $0.41 for each cookie. If you meant 13, it would be $0.38. All you have to do is divide 4.94 by the amount of cookies
Answer:
The constant of proportionality gives you the price per unit at each store.
Step-by-step explanation:
If you assume that the price (y) is directly proportional to the amount (x) you get, the formula is
y = kx
where k is the constant of proportionality.
k = y/x
k has the units of cost per unit, for example, dollars per ounce.
The fewer the dollars per ounce, the better the deal you are getting.
If store A offers apple sauce at $1.29 for 25 oz and Store B offers apple sauce at $2.89 for 50 oz, which is the better deal?
At store A, k = $1.29/25 oz = $0.052/oz or 5.2¢/oz
At store B, k = $2.89/50 oz = $0.058/oz or 5.8¢/oz
The apple sauce is cheaper at Store A.
11/15 + 7 ⇒ rational ⇒ the sum of two rationals is always rational
√14+13 ⇒ irrational ⇒ the sum of a rational and an irrational is always irrational
30×√6 ⇒ irrational ⇒ the product of a nonzero rational and an irrational is always irrational
11/12 × 7/15 ⇒ rational ⇒ the product of two rationals is always rational
