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KiRa [710]
3 years ago
13

Can someone please help me find the equation of the parallel line I will mark u the brainiest

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0

9514 1404 393

Answer:

  y = 1/4x -3/2

Step-by-step explanation:

The "run" (horizontal distance) between the two marked points is 6-(-2)=8.

The "rise" (vertical distance) between the two marked points is 1 -(-1) = 2.

The slope of the line shown is ...

  m = rise/run = 2/8 = 1/4

A parallel line will have the same slope.

__

The y-intercept of the desired line can be found from ...

  b = y -mx

For point (2, -1) and slope 1/4, the y-intercept will be ...

b = -1 -1/4(2) = -3/2

Then the equation of the parallel line is ...

  y = mx +b . . . . . . . line with slope m and y-intercept b

  y = 1/4x -3/2

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Answer:

m=31/2, n=-24. (31/2, -24).

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1.  B. BD

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1.  From the figure,

∠DAB = ∠DAC

Therefore, BD is the bisector of ∠ABC.


2.  From the figure, IG = GH

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