The Fibonacci sequence 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, … is formed by summing two consecutive numbers to get the next number.
adelina 88 [10]
By counting the combinations, we will see that there are 10 combinations such that the sum gives a Fibonacci number.
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How to count the combinations?</h3>
We have two number cubes with 6 outcomes each, such that we have a total of 36 combined outcomes.
For each dice, the outcomes are:
{1, 2, 3, 5, 8, 13}
Now, let's count the combinations that also give a Fibonacci number (these are given by adding two consecutive numbers in the sequence).
I will list each possible red outcome, then the blue outcomes that would give a Fibonacci term, and then we can count the number of combinations.
- Red Blue number of combinations.
- 1 2 1
- 2 1, 2 2
- 3 2, 3 2
- 5 3, 8 2
- 8 5, 13 2
- 13 8 1
Adding the numbers of combinations, we have:
C = 1 + 2 + 2 + 2 + 2 + 1 = 10
There are 10 combinations that give a Fubbonaci number.
If you want to learn more about combinations, you can read:
brainly.com/question/2280026
24000 + 3000x = 30000 + 2400x
3000x - 2400x = 30,000 - 24,000
600x = 6000
x = 6000/600
x = 10 years
Answer:
IJ
Step-by-step explanation:
Answer:
Simplest polynomial: x²+x-12
Step-by-step explanation:
zeroes of polynomial= 3,-4
Therefore,
f(3) =0
f(-4)=0.
By factor Theorem
(x-3) and (x+4) are factors
so simplest polynomial is
(x-3)(x+4)
= x² - 3x + 4x -12
= x² + x -12
.
Hope it helps
