Answer:
![4a^{2} b^{2} c^{3} (\sqrt[3]{b})](https://tex.z-dn.net/?f=4a%5E%7B2%7D%20b%5E%7B2%7D%20c%5E%7B3%7D%20%28%5Csqrt%5B3%5D%7Bb%7D%29)
Step-by-step explanation:
The given expression is :
![\sqrt[3]{(64}a^{6}b^{7} c^{9} )](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2864%7Da%5E%7B6%7Db%5E%7B7%7D%20c%5E%7B9%7D%20%29)
Writing 64 ,a,b,c as cubes we have:
= ![\sqrt[3]{(}4^{3}( a^{2})^3( b^{2})^3.b( c^{3} )^3)](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28%7D4%5E%7B3%7D%28%20a%5E%7B2%7D%29%5E3%28%20b%5E%7B2%7D%29%5E3.b%28%20c%5E%7B3%7D%20%29%5E3%29)
Using radical rule we have :
=
.
The second option is the right answer.
Answer:
Step-by-step explanation:
12 NO WELCOME
:)
Answer:
X=2
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given the following probabilities for events A and B

We want to find P(A ∪ B ∪ C).
Using the inclusion/exclusion formula for the union of three events:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C)−P(B∩C)+P(A∩B∩C).

Therefore, P(A or B or C) = 0.48
The perpendicular line will have the x and y coefficients swapped and one of them negated. We can write the desired line as
9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
3(x -6) -(y -4) = 0
3x -y = 14
An equation for the line of interest is ...
3x -y = 14