Answer:
The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.
Explanation:
We can describe single slit diffraction phenomenon with the equation:
(1)
with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum (
) are small compared to the distance between the screen and the slit (x), we can approximate 
, using this on (1):
solving for y
Note that 
is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find 
, 
add them and divide by two:
Power = work/time
P = 105J/103s
P = <span>1.019 watts</span>
Answer:
1.08x10⁻⁷
Explanation:
F=(GM₁M₂)/r²
=((6.67x10⁻¹¹)(70)(52))/(1.5²)
=2.42788x10⁻⁷/2.25
=1.07905778x10⁻⁷
≈1.08x10⁻⁷
Answer:
The length will be less than 1.0 meter.
Explanation:
By Enistien's theory of special relativity the length contraction is given by
Applying the given values we get
Thus the length is less than 1 meter
<span>you should immediately take your foot off the gas and slow down, turn on your emergency flashers and try to look "under the hood" to see where you are going.
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