Answer:
The value is 
Explanation:
From the question we are told that
The first point charge is 
The second point charge is 
The repulsive force exerted is 
Generally the repulsive force exerted is mathematically represented as
Here k is the coulomb constant with a value 
So
=> 
=>
A magnet is any object that has a magnetic field. It attracts ferrous objects like pieces of iron, steel, nickel and cobalt. In the early days, the Greeks observed that the naturally occurring 'lodestone' attracted iron pieces. From that day onwards began the journey into the discovery of magnets.
These days magnets are made artificially in various shapes and sizes depending on their use. One of the most common magnets - the bar magnet - is a long, rectangular bar of uniform cross-section that attracts pieces of ferrous objects. The magnetic compass needle is also commonly used. The compass needle is a tiny magnet which is free to move horizontally on a pivot. One end of the compass needle points in the North direction and the other end points in the South direction.
The end of a freely pivoted magnet will always point in the North-South direction. The end that points in the North is called the North Pole of the magnet and the end that points South is called the South Pole of the magnet. It has been proven by experiments that like magnetic poles repel each other whereas unlike poles attract each other.
Answer:
hope this helps
Explanation:
an object that's less dense than water floats (eg , ball) because the water it displaces weighs more than the object does. If you've ever tried pushing a beach ball underwater , you've felt this principle in action. As we push the ball down , it pushes back up .
Unf there's no diagram. but this looks like a sort of celsius to fahrenheit temp scale conversion sort of problem.
Answer:
Explanation:
The expression for the second law of motion is given below:
h = 
<u>For first half distance</u>
Object is initially at rest, so its initial speed u = 0
Object falls at half the distance, so h = h/2 where t = t1
Hence, we have
<u>For second half distance:
</u>
Similarly,
where t = t1 + t2 and u= 0
Using equation 2 by equation 1
we obtain 
Hence 
Hence
