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deff fn [24]
3 years ago
14

29. What is the average velocity of an object that moves

Physics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

Average Velocity = - 1.22 cm/s = - 0.0122 m/s

Explanation:

The average velocity of an object is defined as the ratio of the total distance traveled by the object to the total time taken by the object to cover the distance. Therefore, the average velocity of an object can be found by the following formula:

Average Velocity = Total Distance Covered/Total Time Taken

Average Velocity = (Final Position - Initial Position)/Total Time Taken

Average Velocity = (3.7 cm - 6.5 cm)/(2.3 s)

Average Velocity = (- 2.8 cm)/(2.3 s)

<u>Average Velocity = - 1.22 cm/s = - 0.0122 m/s</u>

here, the negative sign indicates the direction of the velocity or the movement of the object is leftwards or towards the origin approaching from right.

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1. Two forces act on a box as follows: F1 = 100 N at 01 = 170° and F2 = 75 N
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Answer:

a)  F = 64.30 N,  b) θ = 121.4º

Explanation:

Forces are vector quantities so one of the best methods to add them is to decompose each force and add the components

let's use trigonometry

Force F1

          sin 170 = F_{1y} / F₁

          cos 170 = F₁ₓ / F₁

          F_{1y} = F₁ sin 170

          F₁ₓ = F₁ cos 170

          F_{1y} = 100 sin 170 = 17.36 N

          F₁ₓ = 100 cos 170 = -98.48 N

Force F2

          sin 30 = F_{2y} / F₂

          cos 30 = F₂ₓ / F₂

          F_{2y} = F₂ sin 30

          F₂ₓ = F₂ cos 30

          F_{2y} = 75 sin 30 = 37.5 N

          F₂ₓ = 75 cos 30 = 64.95 N

the resultant force is

X axis

          Fₓ = F₁ₓ + F₂ₓ

          Fₓ = -98.48 +64.95

          Fₓ = -33.53 N

Y axis

         F_y = F_{1y} + F_{2y}

         F_y = 17.36 + 37.5

         F_y = 54.86 N

a) the magnitude of the resultant vector

let's use Pythagoras' theorem

         F = Ra Fx ^ 2 + Fy²

         F = Ra 33.53² + 54.86²

         F = 64.30 N

b) the direction of the resultant

let's use trigonometry

        tan θ’= F_y / Fₓ

        θ'= tan^{-1}  \frac{F_y}{F_x}

        θ'= tan⁻¹ (54.86 / (33.53)

        θ’= 58.6º

this angle is in the second quadrant

The angle measured from the positive side of the x-axis is

        θ = 180 -θ'

        θ = 180- 58.6

        θ = 121.4º

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