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4 years ago

When two objects interact, the change in momentum of the first object is ______ the change in momentum of the second object.

Physics

1 answer:

Mariulka [41]4 years ago

6 0

Answer:

A. Equal to and Opposite

Explanation:

when there is no External force acting on the system of bodies then Net momentum of the system is Conserved .

Given that there are 2 bodies

Let P₁ as first object's momentum

P₂ as second object's momentum.

Total Momentum =P₁ + P₂

As there is no external force acying on the system

Change in the Total momentum is zero

so,

0 = Δ P₁ + ΔP₂

ΔP₂ = -ΔP₁

negative sign indicates opposite direction.

Both are of equal magnitude.

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(.140*25)+(75*0)= 3.5

3.5 = (.140 + 75)v

(3.5)/(.140 + 75) = v = .04657

which rounds up to .05 m/s

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4 years ago

Consider the two rotating pulley-like systems above. They are identical in every way EXCEPT the mass of the pulley on the left i

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Answer:

Consider the two rotating pulley-like systems above. They are identical in every way EXCEPT the mass of the pulley on the left is concentrated on the outside edge (ring or hoop shape), while the mass of pulley on the right is evenly distributed throughout the pulley (disc or cylinder shape). Given R =0.15m, M =0.6 kg, and m= 0.5 kg. Both pulley systems are initially at rest and the block masses are a height of 0. 8m above the ground.

Explanation:

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3 years ago

A steel cable lying flat on the floor drags a 20 kg block across a horizontal, frictionless floor. A 110 N force applied to the

sammy [17]

Answer:

The mass of the cable is 4.94 kg

Explanation:

It is given that,

Mass of the block, m = 20 kg

Force applied to the cable, F = 110 N

Speed of the block, v = 4.2 m/s

Distance, d = 2 m

Let a is the acceleration of the block. It can be calculated using the third equation of motion as :

$v^2-u^2=2ad$

$(4.2)^2-(0)^2=2a\times 2$

$a=4.41\ m/s^2$

Let m' is the mass of the cable. It can be calculated using the second law of motion as :

$m'=\dfrac{F}{a}-m$

$m=\dfrac{110\ N}{4.41\ m/s^2}-20$

m = 4.94 kg

So, the mass of the cable is 4.94 kg. Hence, this is the required solution.

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3 years ago

A researcher reports an f-ratio with df = 3, 36 for an independent-measures experiment. how many treatment conditions were compa

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The correct option is B.

There were 4 treatment conditions compared in the experiment.

F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.

The researcher reports an F-ratio where the degrees of freedom = 3, 36.

F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.

For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.

Let the treatments which were involved in the study can be denoted by k.

Let the total number of individuals involved in the study can be taken as N.

Then, the treatments will be having degrees of freedom as,

$df_{treatments}$ = k-1