E=F*d/2 = k*d * d/2 =>
d^2= 2*E/k
d= sqrt(2*E/k)=sqrt(2*1J/1000N/m)=sqrt(20m^2)/100=0.045 m = 45 mm
Answer:
Angle of diffraction for second order maxima is θ = 18.941°
Explanation:
From the question it is given that
wavelength of incident light = λ = 541 nm = 541 x 
order of maxima = n =2
diffraction grating has 600 lines per mm
⇒ distance between two slit is 
= 1.66 x 
m
using the relation of Braggs diffraction formula i.e.,
2dsinθ = nλ ..................................(1)
where, d = distance between two lines of grating
θ is the angle of diffraction
n= order of maxima
λ is the intensity of incident photon
on substituting the respected values in relation (1) we get,
2 x 1.66 x m sinθ = 2 x 541 x
⇒ sinθ = 0.3246
⇒ θ = 
= 18.941 °
Answer:
C
Explanation:
- Let acceleration due to gravity @ massive planet be a = 30 m/s^2
- Let acceleration due to gravity @ earth be g = 30 m/s^2
Solution:
- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:
t = v / a
t = v / 30
- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:
t = v / g
t = v / 9.81
- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C
Answer:
Explanation:
Given that
Total race distance is 400m
Her initial velocity was 0m/s²
At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²
Using equation of motion
Let determine her constant acceleration
v²=u²+2as
12²=0²+2×a×100
144=0+200a
144=200a
a=144/200
a=0.72m/s²
Then we want to know her position after another 10second
So total time is 10+12=22seconds
Then, using equation of motion
Let determine his postion
S=ut+½at²
S=0•t+½×0.72×22²
S=0+174.24
S=174.24 m
Her position will be 174.24m
use Newton's gravitational law and 2nd law .....
