Let BS be the event that the patient survives bypass surgery.
Let H be the event that the heart damage will heal.
Then P(BS) = 0.60, and also we have a conditional probability: GIVEN that the patient survives,
the probability that the heart damage will heal is 0.5, that is P(H|BS) = 0.5
We want to know P(BS and H).
Using the formula of the conditional probability:
P(H and BS) = P(H|BS)·P(BS) = (0.6)(0.5) = 0.3
If the three integers are
, then we have
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We can combine the fractions on the left side:

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C-d=b add to both sides d and will get
c-d+d=b+d
c=b+d
hope helped
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Answer:
C
Step-by-step explanation:
Saw it on a quizlet