Answer:
Diameter of the circle = 7
Step-by-step explanation:
The exact question is as follows :
Given - The prom is in need of a floral archway, such as the one below. Segment RC is the perpendicular bisector of segment AH. If AH=6 and RC=2
To find - determine the diameter of the circle that contains AH.
Proof -
Given that,
AH = 6
RC = 2
Let us denote,
CB = x
So,
RB is the radius of the circle. It gives the value x + 2
As AH = 6
⇒AC = CH = 3
Also,
BH is the radius,
So, BH = x + 2
Now,
In triangle CBH,
BH² = CB² + HC²
⇒(x+2)² = x² + 3²
⇒x²+2² + 4x = x² + 9
⇒4 + 4x = 9
⇒4x = 9 - 4
⇒4x = 5
⇒x = 5÷4
⇒x = 1.5
So,
Radius = x + 2
= 1.5 + 2 = 3.5
⇒Radius = 3.5
As we know,
Diameter = 2×Radius
= 2×3.5
= 7
⇒Diameter of the circle = 7
Answer:
x=[15:-5:-25]'
Step-by-step explanation:
In order to create a vector you need to use this command:
x = [j:i:k]'
This creates a regularly-spaced vector x using i as the increment between elements. j is the initial value and k is the final value. Besides you need to add the character ' at the end in order to convert the arrow vector in a column vector
