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alekssr [168]
3 years ago
13

How can goal setting help with academic performance?

Engineering
1 answer:
Zina [86]3 years ago
8 0

Answer:

B.)It is an effective study skill.

Explanation:

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Calculate the resistance of a circuit with 1.5 A and 120 V. Use the appropriate formula from the list of formulas on the
murzikaleks [220]

Answer:

Option C (80 ohms) is the right answer.

Explanation:

The given values are:

Current,

I = 1.5 A

Voltage,

V = I20 V

As we know,

⇒  V=IR

or,

The resistance will be:

⇒  R=\frac{V}{I}

On substituting the values, we get

⇒      =\frac{120}{1.5}

⇒      =80 \ ohms

5 0
2 years ago
. (20 pts) A horizontal cylindrical pipe (k = 10 W/m·K) has an outer diameter of 15 cm and a wall thickness of 5 cm. The pipe is
nata0808 [166]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

7 0
3 years ago
Explain why veracity, value, and visualization can also be said to apply to relational databases as well as Big Data.
Hatshy [7]

Answer:

Veracity, Value and Visualization are not only the characteristics of Big Data but are also the characteristics of relational databases. Veracity of data is issue with smallest data stores this is the reason that it is important in relation...

5 0
2 years ago
A socket can be driven using any of the following except for (A) a socket ratchet
AfilCa [17]

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a socket can be driven by a flexible head socket wrench, I believe

4 0
3 years ago
A 179 ‑turn circular coil of radius 3.95 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicu
suter [353]

Answer:

The energy, that is dissipated in the resistor during this time interval is 153.6 mJ

Explanation:

Given;

number of turns, N = 179

radius of the circular coil, r = 3.95 cm = 0.0395 m

resistance, R = 10.1 Ω

time, t = 0.163 s

magnetic field strength, B = 0.573 T

Induced emf is given as;

emf= N\frac{d \phi}{dt}

where;

ΔФ is change in magnetic flux

ΔФ  = BA = B x πr²

ΔФ  = 0.573 x π(0.0395)² = 0.002809 T.m²

emf = N\frac{d \phi}{dt} = 179(\frac{0.002809}{0.163} ) = 3.0848 \ V

According to ohm's law;

V = IR

I = V / R

I = 3.0848 / 10.1

I = 0.3054 A

Energy = I²Rt

Energy = (0.3054)² x 10.1 x 0.163

Energy = 0.1536 J

Energy = 153.6 mJ

Therefore, the energy, that is dissipated in the resistor during this time interval is 153.6 mJ

6 0
3 years ago
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