Answer:
The average loss for this device is $10.90
Explanation:
Given data
Specification = 24 +/- 0.4 Amps
average quality cost = $32.00
average value y = 23.9
standard deviation s = 0.211 Amps
32 = k(24.4 - 24)²
32 = k(0.4)² = k(0.16)
k = 32/0.16 = 200
To evaluate average loss, use
L = k{s² + (y - T)²}
T = 24A
L = 200{0.211² + (23.9 - 24)²}
L = $10.90
The average loss for this device is $10.90
Whatever ur designing has to fit the requirements.
uhh , not all girls are like that. many of em these days are more career oriented and thats good i guess , so if anything ur just being judgy a f here.
Answer:
Explanation:
Since we are considering electron and hole drift velocities, then electric field E will have to be taken into consideration as well.
Where E = V/d...... 1
Drift velocity (u) = -μE. For electron.... 2
Drift velocity (v) = μE. For hole...... 3
Given that : V = 5V and d = 10 um (micro meter)
From equation 1
E = V/d
E = 5V/10×10^-4cm
E = 5V ÷1/1000
E = 5×1000
E = 5000v/cm
From equation 2
Un = -μE.
Un = - 1350cm^2/vs × 5000
= -6750000cm/s
From equation 3
Vp = μE
= 480cm^2/vs × 5000
= 2400000cm/s
Since it was stated in the question that we should contrast between hole drift and electron drift.
6750000/2400000
= 2.8125
Hence the electron drift velocity is 2.8 times that of hole drift velocity indicating that the speed of the electron through the silicon was faster.
Answer:
1. A.True
2. B.False
3. B.False
4. A.True
5. A.True
6. A.True
7. A.True
8. B.False
9. B.False
10. A.True
11. B.False
12. A.True
13. A.True
14. B.False
15. B.False
16. A.True
Explanation:
Most steels have endurance and fatigue limit about half the Tensile strength. Tensile strength of material is the limit of stress at which material then breaks. The tensile stress in a bolt is calculated through tensile force.