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Alex777 [14]
3 years ago
14

A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s

. It passes the point x = 375 m with a speed of 50.0 m/s at t = 20.0 s . Find the average velocity between t = 3.00 s and t = 20.0 s . Express your answer with the appropriate units.
Find the average acceleration between t = 3.00 s and t = 20.0 s .
Express your answer with the appropriate units.
Physics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

a) v=20.3m/s

b) a=2.35m/s^2

Explanation:

From the exercise we know:

x_{1}=30m; v_{1}=10m/s; t_{1}=3s

x_{2}=375m; v_{2}=50m/s; t_{2}=20s

The formula for average velocity is:

v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}

a) v=\frac{375m-30m}{20s-3s}=20.3m/s

The formula for average acceleration is:

a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}

b) a=\frac{(50-10)m/s}{(20-3)s}=2.35m/s^2

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