The sphere’s Electric potential energy is 1.6*
J
Given,
q=6. 5 µc, V=240 v,
We know that sphere’s Electric potential energy(E) = qV=6.5*
=1.6*
J
<h3>Electric potential energy</h3>
The configuration of a certain set of point charges within a given system is connected with the potential energy (measured in joules) known as electric potential energy, which is a product of conservative Coulomb forces. Two crucial factors—its inherent electric charge and its position in relation to other electrically charged objects—can determine whether an object has electric potential energy.
In systems with time-varying electric fields, the potential energy is referred to as "electric potential energy," but in systems with time-invariant electric fields, the potential energy is referred to as "electrostatic potential energy."
A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?
Learn more about Electric potential energy here:
brainly.com/question/24284560
#SPJ4
Answer:
Here we do not have the vector, but I will try to give a kinda general solution to this type of problem.
If the vector is written as (a, b, c) we have that the force in the x-axis is of a Newtons, in the y-axis is of b Newtons, and in the z-axis is of c Newtons.
Then, we can calculate the total magnitude of this force as:
F = √( a^2 + b^2 + c^2)
wich gives us the total magnitude of the force, but not a direction or anything like that, this is just a scalar.
Answer:
it depends on the weight's ratio
(sorry)
Solution :
Given :
Mass of the object attached to the spring, m = 2 kg
Velocity of the object as it moves, V = 5 m/s
Amplitude of the object as it swings, A = 2.5 m
We have to find the frequency of the object.
We known,

Therefore, 

f = 0.32 Hz
Therefore the frequency of the object is 0.32 hertz when the amplitude of the 2 kg mass is 2.5 m moving a speed of 5 m/s.