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uranmaximum [27]
3 years ago
7

What is the next number in this sequence and why?

Mathematics
1 answer:
vekshin13 years ago
3 0

2,6,15,31,......

6-2=4=2X2

15-6=9=3X3

31-15=16=4X4

So the next number should be 31+5X5=56

hope this helps :)

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-3x(x - 4) + 2 - (5 - x)
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Answer:

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Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-620=\dfrac{749-620}{70-30}(x-30)

y-620=\dfrac{129}{40}(x-30)

y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)

y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}

Adding 620 on both sides, we get

y=\dfrac{129}{40}x-\dfrac{387}{4}+620

y=\dfrac{129}{40}x+\dfrac{2480-387}{4}

y=\dfrac{129}{40}x+\dfrac{2093}{4}

We need to find the y-value for x=57.

y=\dfrac{129}{40}(57)+\dfrac{2093}{4}

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y=707.075

y\approx 707.1

Therefore, the required linear equation for the given situation is y=\dfrac{129}{40}x+\dfrac{2093}{4} and the average score for persons taking a 57-hour review course is 707.1.

4 0
2 years ago
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