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kirill [66]
3 years ago
6

4. Using a complete sentence, state what would most likely happen to the production of oxygen by duckweed plants if the intensit

y and duration of exposure to light were increased.​
Biology
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

See the answer below

Explanation:

<em>If the intensity and duration of exposure to light are increased for a duckweed plant, the rate of photosynthesis would increase and this would lead to an increase in the amount of oxygen produced.</em>

From the equation of photosynthesis:

6CO_2 + 6H_2O + light --> C_6H_1_2O_6 + 6O_2

the more the rate of photosynthesis, the more the amount of oxygen produced. Also, an increase in the intensity of light generally increases the rate of photosynthesis (and oxygen production) provided that other reactants can catch up. The rate of photosynthesis would become limited by the reactant that is available in the lowest quantity.

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Which is not an example of someone maintaining homeostasis
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The answer is D. a man bleeding from a cut.

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What type of chemical bond is found between the
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Which of the following is true about natural selection? ​
Anna007 [38]

The options for this question are:

- Requires genetic variation

- Results in descent with modification

- Involves differential reproductive success

- All of the above

Answer:

<u><em>The correct option is d) All of the above</em></u>

Explanation:

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3 years ago
Which human activity would help reduce the amount of carbon dioxide in the atmosphere
Alex Ar [27]

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The LMand LNalleles at the MN blood-group locus exhibit codominance. Give the expected genotypes and phenotypes and their ratios
Dmitry [639]

Answer:

Please find the expected genotypes and phenotypes of the progenies of each cross below.

Explanation:

In the MN blood-group locus of the gene, alleles LM and LN exhibit codominance i.e one allele is not dominant or recessive to the other, hence, they are both expressed when they occur in a heterozygous state (MN).

Considering the following crosses (find the punnet square attached);

a)LMLM x LMLN - The progeny are LMLM and LMLN in the genotypic ratio 1:1. Phenotypic ratio is Blood type M (1) : blood type MN (1)

b) LNLN x LNLN - The progeny are all LNLN offsprings with a phenotypic and genotypic ratio 4:0. All offsprings will have a blood type N (4)

c) LMLN x LMLN - The progenies are LMLM, LMLN and LNLN in the genotypic ratio 1:2:1 respectively. The phenotypic ratio is Blood type M (1) : L

Blood type MN (2) : Blood type N (1)

d) LMLN x LNLN - The progeny are LMLN and LNLN with genotypic ratio 1:1 and phenotypic ratio blood type MN (1) : blood type N (1)

e) LMLM x LNLN - The progeny are all LMLN offsprings with penotypic ratio blood type MN (4)

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