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dimaraw [331]
3 years ago
10

(-10x-8)-70 (4x-11) + 46 -43(6x6) -54+ (8x5)

Mathematics
1 answer:
STatiana [176]3 years ago
7 0
I feel like you just put random numbers in to waste someone time... but I did the problem any way.

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Find the indicated values, where g(t)=t^2-t and f(x)=1+x g(f(2)+3)
sleet_krkn [62]

Answer:

g(f(2)+3)=30

Step-by-step explanation:

We have the two functions:

g(t)=t^2-t\text{ and } f(x)=1+x

And we wish to find:

g(f(2)+3)

First, let’s find f(2) first. So, we will substitute 2 for x for f(x):

f(2)=1+(2)=3

Hence, we can now substitute 3 for f(2):

g(f(2)+3)=g(3+3)=g(6)

Now, we can find g(6). Substitute 6 for t for g(t):

g(6)=(6)^2-(6)=36-6=30

Therefore:

g(f(2)+3)=30

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3 years ago
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