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3 years ago

Which pair of variables would most likely have a negative association?

Mathematics

1 answer:

Svetlanka [38]3 years ago

8 0

Answer:

C the temperature and the number of votes a candidate for the school president receives.

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(x^3)^9 = A: x^12 B: x^27 C: x^3 D: x^6

Grace [21]

$(x^3)^9=x^{27}$

3 0

4 years ago

I need help please on this math

Zigmanuir [339]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone double check my work for this problem? I got 38°??

scoundrel [369]

We need to use Law of sine.

sin A/a = sin C/c
sin A/|CB| = sin C/|AB|

sin A/14 = sin(118⁰)/ 20
sin A = (14*sin(118⁰))/ 20

A=arcsin((14*sin(118⁰))/ 20) ≈ 38⁰

4 0

3 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

Given cos theta=4/9 and csc theta 0 find sin theta and tan theta

Korvikt [17]

The correct question is
Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta

we know that
csc theta=1/sin theta
if csc theta < 0
then
sin theta < 0

we have that
cos theta=4/9

we know that
sin² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9

the answer Part a) is
sin theta=-√65/9

Part b) find tan theta

tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4

the answer part b) is
tan theta=-√65/4

5 0

3 years ago

Read 2 more answers