Answer : The ratio of effusion rates for helium and argon is 3.2 : 1
Solution : Given,
Molar mass of Helium = 4 g/mole
Molar mass of Argon = 40 g/mole
Rate of effusion : It is defined as the rate of effusion of a gas is inversely proportional to the square root of the molar mass of the gas.
Formula used :
where, M is the molar mass.
Now put all the given values in this expression, we get
Therefore, the ratio of effusion rates for helium and argon is 3.2 : 1
Answer:
chemical change
Explanation:
A physical change is one that makes changes to the physical properties of matter. In many cases, the difference is usually reversible. Examples include boiling, melting, freezing, the magnetization of metals, etc.
A chemical change is one in which a new kind of matter is formed. It is usually accompanied by energy changes, i.e., the evolution or absorption of energy in the form of heat or light. This process is not easily reversible. Examples include; combustion, rusting of iron, precipitation, the souring of milk, etc.
From the question given, the combination of two clear liquid in a beaker which results to formation of bubbles and changes in coloration of the solution is a chemical change.
Answer:
When an atom of sodium and an atom of fluorine combine to form the salt, sodium fluoride, an ionic bond, is formed.
Explanation:
Answer:
130 moles of water might be produced by the reaction.
Explanation:
We state the equation for production of water:
2H₂(g) + O₂ (g) → 2H₂O (l)
Moles of hydrogen: 130
Moles of oxygen: 60
We state that the limting reactant is the oxygen
For 2 moles of hydrogen, we need 1 mol of oxygen
For 130 moles of hydrogen, we would need 65 moles, and we only have 60. Ratio is 2:1
1 mol of O₂ can produce 2 moles of water
Then, 60 moles of O₂ will produce (60 . 2) /1 = 130 moles
They both conduct electricity at least partially
