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stepladder [879]
2 years ago
9

Find the number of moles of water that can be formed if you have 130 mol of hydrogen gas and 60 mol of oxygen gas.

Chemistry
1 answer:
Brut [27]2 years ago
7 0

Answer:

130 moles of water might be produced by the reaction.

Explanation:

We state the equation for production of water:

2H₂(g) + O₂ (g) → 2H₂O (l)

Moles of hydrogen: 130

Moles of oxygen: 60

We state that the limting reactant is the oxygen

For 2 moles of hydrogen, we need 1 mol of oxygen

For 130 moles of hydrogen, we would need 65 moles, and we only have 60. Ratio is 2:1

1 mol of O₂ can produce 2 moles of water

Then, 60 moles of O₂ will produce (60 . 2) /1 = 130 moles

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laiz [17]
<h3>Answer:</h3>

150 g Si

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Use Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.2 × 10²⁴ atoms Si

[Solve] grams Si

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Si - 28.09 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.2 \cdot 10^{24} \ atoms \ Si(\frac{1 \ mol \ Si}{6.022 \cdot 10^{23} \ atoms \ Si})(\frac{28.09 \ g \ Si}{1 \ mol \ Si})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 149.266 \ g \ Si

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. Instructed to round to 2 sig figs.</em>

149.266 g Si ≈ 150 g Si

4 0
3 years ago
Look at the atom models you made in today’s activities. Name the three parts of the atom. A. protons, neutrons, and electrons B.
Musya8 [376]
D, protons,molecules, and electrons
5 0
3 years ago
La columna de la izquierda corresponde a los tipos de sales y la columna derecha a los tipos de fórmula que presentan. Relaciona
Galina-37 [17]

Answer:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)X

Explanation:

¡Hola!

En este caso, de acuerdo con el concepto de sal, la cual está generalmente dada por la presencia de al menos un metal y un no metal, es posible encontrar cuatro tipos de estas; hidrácidas, oxácidas, básicas y ácidas, en las que las primeras dos son neutras pero la segunda tiene presencia de oxígeno, la tercera tiene iones hidróxido adicionales y la cuarta iones hidrógeno de más.

Debido a la anterior, es posible relacionar cada pareja de la siguiente manera:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)XO

En las que M se refiere a un metal, X a un no metal, H a hidrógeno y O a oxígeno.

¡Saludos!

3 0
3 years ago
describe the behavior of the molecules in a liquid. Explain this behavior in terms of intermolecular forces.
tigry1 [53]

Answer:

Molecules in liquids are held to other molecules by intermolecular interactions, which are weaker than the intramolecular interactions that hold the atoms together within molecules and polyatomic ions.

5 0
3 years ago
Consider a solution that contains 0.274 M potassium chloride and 0.155 M magnesium chloride.
solong [7]

Answer:

Concentration of chloride ions = 0.584M

Explanation:

The step by step calculations is shown as attached below.

3 0
3 years ago
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