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3 years ago

Find the number of moles of water that can be formed if you have 130 mol of hydrogen gas and 60 mol of oxygen gas.

Chemistry

1 answer:

Brut [27]3 years ago

7 0

Answer:

130 moles of water might be produced by the reaction.

Explanation:

We state the equation for production of water:

2H₂(g) + O₂ (g) → 2H₂O (l)

Moles of hydrogen: 130

Moles of oxygen: 60

We state that the limting reactant is the oxygen

For 2 moles of hydrogen, we need 1 mol of oxygen

For 130 moles of hydrogen, we would need 65 moles, and we only have 60. Ratio is 2:1

1 mol of O₂ can produce 2 moles of water

Then, 60 moles of O₂ will produce (60 . 2) /1 = 130 moles

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2 H2(g) + O2(g) → 2 H2O(g)

alexgriva [62]

Answer:

77 L of water can be made.

Explanation:

Molar mass of $O_{2}$ = 32 g/mol

So, 55 g of $O_{2}$ = $\frac{55}{32}$ mol of $O_{2}$ = 1.72 mol of $O_{2}$

As hydrogen is present in excess amount therefore $O_{2}$ is the limiting reagent.

According to balanced equation, 1 mol of $O_{2}$ produces 2 mol of $H_{2}O$ .

So, 1.72 mol of $O_{2}$ produce $(2\times 1.72)$ mol of $H_{2}O$ or 3.44 mol of $H_{2}O$ .

Let's assume $H_{2}O$ gas behaves ideally at STP.

Then, $P_{H_{2}O}.V_{H_{2}O}=n_{H_{2}O}.R.T$ , where P, V, n, R and T represents pressure, volume, no. of moles, gas constant and temperature in kelvin scale respectively.

At STP, pressure is 1 atm and T is 273 K.

Here, $n_{H_{2}O}$ = 3.44 mol and R = 0.0821 L.atm/(mol.K)

So, $(1atm)\times V_{H_{2}O}=(3.44mol)\times (0.0821L.atm.mol^{-1}.K^{-1})\times (273K)$

$\Rightarrow$ $V_{H_{2}O}=77L$

Option (b) is correct.

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3 years ago

How will an increase in pressure affect the following chemical equilibrium:

tresset_1 [31]

Answer:

Will up 2NO

Explanation:

The future gas particle will be increased by about 4.2. (estimated) Pressure is absorbed, and by the gas, created heavier.

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3 years ago

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An experiment was set up to test the hypothesis that all plants will grow faster in a "super soil" versus regular potting soil.

dolphi86 [110]

Answer:

add more types of plants

Explanation:are you kidding me i’m doing this stuff and i’m in 7th grade

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4 years ago

If you have 5.22*1022 molecules of glucose (C6H12O6) how many grams is this?

lianna [129]

Answer:

5.22*1022 molecules of glucose (C6H12O6) is equal to 15.08 grams

Explanation:

Number of molecule of glucose in one mole $= 6.023 * 10^{23}$

Now mass of one mole of glucose $= 180$ grams

Number of moles in $6.023 * 10^{23}$ molecules of glucose $= 1$

Number of moles in $1$ molecules of glucose = $\frac{1}{6.023 * 10^{23}}$

Number of moles in $5.22 * 10^{22}$ molecules of glucose = $\frac{5.22* 10^{22}}{6.023 * 10^{23}}$ = $0.083$ moles

Weight of $0.083$ moles

$= 0.083 * 180\\= 15.08$ grams

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Global Warming is tthe cause

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