<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
4.3496 miles.
HTH (Hope This Helps)
Since both y’s are negative you can combine them to make -6y=1 then you divide -6 on each Side to get y=6
Answer:
2
1
3
+
2
8
2
−
4
9
−
1
2
2
−
1
6
+
2
8
Step-by-step explanation:
