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3 years ago

Pls answer my question!! I'm sooo confused!!!!!!!!

Mathematics

2 answers:

solmaris [256]3 years ago

8 0

Answer:

It letter C!!

Step-by-step explanation:

oTheres no way you can write a negative twice with a top and bottom You can put the negative in the middle or one on ONE number top or bottom but never can be both

kompoz [17]3 years ago

6 0

Answer:

For A and B where the negative is doesn't matter since the decimal form of both of these fractions is equal to -0.66667 (they are equal no matter where u put the negative sign). the decimal form of - 2/3 is also -0.666667. A good rule to know is that a negative divided by a negative or a negative multiplied by a negative is always a positive. in c, -2/-3 is actually 0.66667 meaning its incorrect.

Hard to explain through writing but hoped this helped

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The formula F = 1.8C + 32 is used to convert temperatures from degrees Celsius, °C, to degrees Fahrenheit, °F. Find the temperat

lapo4ka [179]

Answer:

68F

Step-by-step explanation:

Given data

The formula F = 1.8C + 32

we want to find F for C= 20°C

Substitute into the formula we have'

F = 1.8(20) + 32

F=36+32

F=68

Hence the value of 20°C in Fahrenheit is 68F

3 0

3 years ago

The side lengths of triangle ABC are written in terms of the variable p, where p ≥ 3. Triangle A B C is shown. Side A B has a le

Aliun [14]

Answer:

Angle C > Angle A > Angle B

Step-by-step explanation:

In Δ ABC, the sides AB = 4p - 1, BC = 3p and CA = p + 4, where p ≥ 3.

Assume, p = 3, then AB = 11 units, BC = 9 units and CA = 7 units.

We know, the angle of a triangle is larger for the larger length of the opposite side.

So, Angle C > Angle A > Angle B

Therefore, option c is correct. (Answer)

8 0

3 years ago

Read 2 more answers

Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)

sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

$A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)$

Now, to get the area of triangle ABC:

$Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|$

$Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|$

$Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|$

On solving we get:

$Area\,of\,triangle\,=25.$

In Δ ADC:

$A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)$

Now, to get the area of triangle ADC:

$Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|$

$Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|$

On solving it by same process as above we get:

$Area\,of\,triangle\,=114$

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

$25+114\\=25+114\\=139\ unit^2$

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0

3 years ago

A car was sold at $34000. That price was 85℅ of the orginal price. What was the original price?

Art [367]

Hey there! The answer is $40000

<span>A car was sold at $34000. That price was 85℅ of the orginal price.
When we know 85% of the original price we can find 1% of this price by dividing by 85.

1% of the original price = $34000 / 85 = $400
</span>When we know 1% of the original price we can find 100% of this price by multiplying by 100.

100% of the original price = original price = $400 * 100 = $40000
The answer is $40000

~ Hope this helps you!

3 0

4 years ago

1. *

Elenna [48]

Answer:

(1) P(A) + P(B) - P(AB)

Step-by-step explanation:

5 0

3 years ago