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3 years ago

Why is adding 3/9 and 6/9 different from multpying the two fractions? Explain

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ When you add fractions, you have to have the same denominator whereas, when you multiply them, you don't have to. (In this case the denominators are already the same.) Also, multiplying the fractions would make the result smaller whereas adding them would make it larger.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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dlinn [17]

The answer is B.24x^6-18x^5=6x^5(4x-3)

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3 years ago

∆ABC has A(-3, 6), B(2, 1), and C(9, 5) as its vertices. The length of side AB is units. The length of side BC is units. The len

leonid [27]

Answer:

AB = 7.07 units

BC = 8.06 units

AC = 12.04 units

Step-by-step explanation:

To find the length for each side of the triangle, apply the distance formula between each pair of vertices.

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07$

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$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06$

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$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04$

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3 years ago

How do you make fractions into decimals

ahrayia [7]

Answer:

you divide the nominator by the denominator

Step-by-step explanation:

For example:

10/15

so 10 divided by 15= .6666...

10/15 as a decimal is .6 repeating

3 0

3 years ago

Read 2 more answers

The length of a box is 4 inches longer than its width, and the height is 2 inches shorter than the width. which equation can you

andreev551 [17]

L=w+4 this shows the length is 4 inches longer than width
h=w-2 this shows the height is 2 inches shorter than the width
volume=lwh
so 240=lwh=(w+4)(w)(w-2)
simplify and solve to find the width then you can use that to find the other values as well.

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3 years ago

A rectangular container has a base that is 12 inches long and 8 inches wide. The container is filled with water to a height of 6

valina [46]

Answer: the length of one edge of the square base of the second container is 6 inches.

Step-by-step explanation:

The formula for determining the volume of a rectangular container is expressed as

Volume = length × width × height

Considering the first container,

Length = 12 inches

Width = 8 inches

Height to which the water is filled is 6 inches.

Therefore, volume of water in the container is

12 × 8 × 6 = 576 inches³

Considering the second container,

Height of water = 16 inches

Let L represent the length of the square base. Then the area of the square base is L²

Volume of water would be 16L²

Since the water in the first container was poured into the second container, then

16L² = 576

L² = 576/16 = 36

L = √36

L = 6 inches

7 0

3 years ago