The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
Given that,
The points A (3, -5) and A' (2, -3).
We have to determine,
The distance between point A and A'.
According to the question,
The distance between two points is determined by using the distance formula.
Then,
The distance between points A (3, -5) and A' (2, -3) is,
Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
For more details refer to the link given below.
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
