Question

Write a sine function that has an amplitude of 5, a midline of 3 and a period of 1/8.

Answer 1

Answer:

y=5sin(16pix)+3

Step-by-step explanation:

Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.

y=sin(x) has period 2pi.

So y=sin(bx) has period 2pi/b.

We want 2pi/b=1/8.

Cross multiplying gives: 16pi=b

y=5sin(16pix+c)+d

d=3 since we want midline y=3.

y=5sin(16pix+c)+3

We can choose c=0 since we aren't required to have a certain phase shift.

y=5sin(16pix)+3