1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grin007 [14]
2 years ago
6

Write a sine function that has an amplitude of 5, a midline of 3 and a period of 1/8.

Mathematics
1 answer:
vodomira [7]2 years ago
6 0

Answer:

y=5sin(16pix)+3

Step-by-step explanation:

Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.

y=sin(x) has period 2pi.

So y=sin(bx) has period 2pi/b.

We want 2pi/b=1/8.

Cross multiplying gives: 16pi=b

y=5sin(16pix+c)+d

d=3 since we want midline y=3.

y=5sin(16pix+c)+3

We can choose c=0 since we aren't required to have a certain phase shift.

y=5sin(16pix)+3

You might be interested in
Plot each pair of points in the Cartesian plane and solve for the distance between them. Write your answer on a separate one who
sammy [17]

Answer:

hame naghi ahta

Step-by-step explanation:

8 0
2 years ago
Help please (see below)
Elden [556K]

Answer:

The quotient is 10x + 16

The remainder is 28x^2 + 10x +22

4 0
3 years ago
Cynthia Besch wants to buy a rug for a room that is 24 ft wide and 33 ft long. She
qaws [65]
<h3>Answer:   16 ft by 25 ft</h3>

=========================================================

Explanation:

Refer to the diagram below.

The outer dimensions 24 ft and 33 ft shrink down to 24-2x ft and 33-2x ft respectively. This subtraction of 2x is due to subtracting two copies of x per side.

The carpet has area of (24-2x)(33-2x)

Cynthia can afford to buy 400 sq ft of carpet

So we set 400 equal to that previous expression and solve for x

(24-2x)(33-2x) = 400

24(33-2x) - 2x(33-2x) = 400

792-48x - 66x + 4x^2 = 400

4x^2 - 114x + 792 = 400

4x^2 - 114x + 792-400 = 0

4x^2 - 114x + 392 = 0

From here, use the quadratic formula to isolate x.

Plug in a = 4, b = -114, c = 392

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-114)\pm\sqrt{(-114)^2-4(4)(392)}}{2(4)}\\\\x = \frac{114\pm\sqrt{6724}}{8}\\\\x = \frac{114\pm82}{8}\\\\x = \frac{114+82}{8} \ \text{ or } \ x = \frac{114-82}{8}\\\\x = \frac{196}{8} \ \text{ or } \ x = \frac{32}{8}\\\\x = 24.5 \ \text{ or } \ x = 4\\\\

The two possible solutions are x = 24.5 and x = 4

But if x = 24.5, then 24 - 2x = 24 - 2*24.5 = -25 which isn't possible. We cannot have a negative width or negative length for the carpet.

Luckily x = 4 does work since

24 - 2x = 24 - 2*4 = 16

33 - 2x = 33 - 2*4 = 25

Both results are positive.

Therefore, the carpet has dimensions of <u>16 ft by 25 ft</u>

Check: 16*25 = 400, so the answer is confirmed

5 0
1 year ago
Which number is opposite of -5 in both its value and direction it lies on a number line?
ASHA 777 [7]

Answer:

The opposite of - 5 would be 5

Step-by-step explanation:

Because opposite number only means a number with an oposite sign

6 0
2 years ago
An ant travels at speed of 3 inches per second. How many feet will the ant travel in 2 hours?
GarryVolchara [31]

64,800 inches in 2 hours I think

6 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP I WILL MARK YOU BRAINLIEST
    8·2 answers
  • The sentence on the bottom not on the top.<br><br> GIVE U 100 POINTS PROMISE
    6·2 answers
  • .
    9·1 answer
  • What is the measure of SRT? 69 79 99 or 101 degrees
    5·2 answers
  • No one ever answers my questions pls i need help
    14·1 answer
  • 4. Express the following rational number in its lowest form :
    7·2 answers
  • Please help i need the answers fast <br><br><br><br><br><br> A 19<br> B 28<br> C 33<br> D 35
    6·1 answer
  • Solve 2x - 16 ≥ 32 - 6x.
    6·1 answer
  • For a lower tail hypothesis test with a sample size of 10 and a .10 level of significance, the critical value of the test statis
    5·1 answer
  • The ratio of red sweets to sweets that are not red is 2:3
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!