Write a sine function that has an amplitude of 5, a midline of 3 and a period of 1/8.
1 answer:
Answer:
y=5sin(16pix)+3
Step-by-step explanation:
Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.
y=sin(x) has period 2pi.
So y=sin(bx) has period 2pi/b.
We want 2pi/b=1/8.
Cross multiplying gives: 16pi=b
y=5sin(16pix+c)+d
d=3 since we want midline y=3.
y=5sin(16pix+c)+3
We can choose c=0 since we aren't required to have a certain phase shift.
y=5sin(16pix)+3
You might be interested in
Answer:
8.75×10^3
Step-by-step explanation:
here is the answer
Step-by-step explanation:
(- 4xy - 2) - 5(xy - 2) - 1
-4xy - 2 - 5xy + 10 - 1
Solving like terms
-9xy + 7
Answer:
The area of the shaded region is the difference between the areas of the rectangle and the square.
Step-by-step explanation:
Answer:
Since 6 lemons are used to make 4 cups of lemonade, then are used 
of lemon per cup of lemonade, or are make 
cups of lemonade per lemon.
