Write a sine function that has an amplitude of 5, a midline of 3 and a period of 1/8.
1 answer:
Answer:
y=5sin(16pix)+3
Step-by-step explanation:
Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.
y=sin(x) has period 2pi.
So y=sin(bx) has period 2pi/b.
We want 2pi/b=1/8.
Cross multiplying gives: 16pi=b
y=5sin(16pix+c)+d
d=3 since we want midline y=3.
y=5sin(16pix+c)+3
We can choose c=0 since we aren't required to have a certain phase shift.
y=5sin(16pix)+3
You might be interested in
26 1/5 is the answer i got
Answer:
28.4484
Step-by-step explanation:
2.6 = 2.600
So, 2.6 is not bigger than 2.661
Answer:
505.4 in²
Step-by-step explanation:
½d2= 19×tan 35° = 19×0.7 = 13.3 in
d2 = 2×13.3 = 26.6 in
d1 = 2×19=38 in
the area of Rhombus =
½×38×26.6 = 505.4 in²
The answer is Area= 50.265 and the circumference is 25.133