If a rectangle's length is 7 more than 4 times the width and the perimeter is 54 what are the dimensions of the rectangle?

1 answer:

4 0

Let w = width of the rectangle
4w+7 = length of the rectangle 

perimeter = 2 lengths + 2 widths 

2w + 2(4w+7) = 54 
2w + 8w + 14 = 54 
10w = 40 
w = 4 
4w+7 = 23 

dimensions of rectangle: 
width = 4 
length = 23 hope this helps

You might be interested in

The length of rectangle is 5 cm greater than its width. The perimeter is 106cm. Find the dimensions of the rectangle.

antiseptic1488 [7]

Width-24 Length-29

Two sides of the rectangle are 5 cm bigger than the other two. So you would add the two 5 cm together (10cm). If you take the 10 cm off you (106-10) you will get a square. Then all you have to do is divide 96 by 4 (24), and add back on the two 5cm from the beginning to the length (29).

4 0

2 years ago

A + b = c

ipn [44]

Answer:

a=9

b=9

c=18

Step-by-step explanation:

c(a+b)+a+b=36

2a+2b=36

a+b=18