Question

An astronaut, whose mission is to go where no one has gone before, lands on a spherical planet in a distant galaxy.

Answer 1

Answer:

$M = 1.77 \times 10^{27} kg$

Explanation:

As we know that the that the Astronaut dropped a stone on the surface of the planet takes 0.420 s to fall a distance of d = 1.90 m

so we will have

$y = \frac{1}{2}g t^2$

$1.90 = \frac{1}{2}g(0.420^2)$

$g = 21.5 m/s^2$

now we know that the acceleration due to gravity is given as

$g = \frac{GM}{R^2}$

so we will have

$21.5 = \frac{(6.67 \times 10^{-11})M}{(7.40\times 10^7)^2}$

$M = 1.77 \times 10^{27} kg$