Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³

Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².
Answer:
2991.42 N
Explanation:
For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.
initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s
final momentum; p2 = 0, because final velocity is 0 m/s
Thus,
impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s
Finally, impulse= Force x time,
Thus, Force = Impulse/time
Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N
They need resources such as food and sometimes water
The vertical distance through which the book falls is determined as 1,048.8 m.
<h3>Height of the book fall</h3>
The vertical distance through which the book falls is calculated as follows;
h = vt + ¹/₂gt²
where;
- h is height of fall
- v is initial vertical velocity
- g is acceleration due to gravity
h = (16 x sin52)(13.4) + (0.5)(9.8)(13.4²)
h = 1,048.8 m
Thus, the vertical distance through which the book falls is determined as 1,048.8 m.
Learn more about height of fall here: brainly.com/question/15611384
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Answer:
a) 3000 Hz;
b) 30 dB;
c) 1000 times.
Explanation:
a) From the human audiogram given on the figure below the black line represents the threshold for hearing the sound at each frequency. We see that the least intensity is necessary for the frequency of about 3000 Hz.
b) Using the same audiogram we see that we would need the sound of the intensity of about 30dB.
c) The least perceptible sound at 1000 Hz must be 0dB while at 100 Hz it is 30dB. These are logarithmic quantities. To transform them to the linear quantities we use the formula

where
is the hearing threshold at 1000 Hz.
Therefore we have the following

is the threshold at 1000Hz and
is the threshold at 100Hz.
By exponentiating we have

Now dividing these two equations we get

Therefore, the least perceptible sound at 100Hz is 1000 times more intense than the least perceptible sound at 1000Hz.
Note: I got these values unisng the audiogram that is attached here. The one that you have might be slightly different and might yield different answers.