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Pavlova-9 [17]
3 years ago
14

Your study buddy claims that an electron always experiences a force in an electric field, but not always in a magnetic field. do

you agree? why or why not?
Physics
1 answer:
timurjin [86]3 years ago
4 0
It's true charged particles are always acted on by an electric field.when the velocity of the electron is parallel to the magnetic field, the magnetic force vanishes.
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The position of a charge in an electric field gives it _____electric
kykrilka [37]

Answer:

The space surrounding a charged object is affected by the presence of the charge; an electric field is established in that space. A charged object creates an electric field - an alteration of the space or field in the region that surrounds it. Other charges in that field would feel the unusual alteration of the space.

Explanation:

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3 years ago
How does the electric force between two charged particles change if particle's charge is reduced by a factor of 3?
MAVERICK [17]

The force between two charges is proportional to the product of the charges.

If only one of the charges is reduced by a factor of 3, then the force is reduced by a factor of 3.

If both charges are reduced by a factor of 3, then the force is reduced by a factor of 9.

3 0
4 years ago
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Liula [17]
<h2>Answer: True  </h2><h2></h2>

Each atom emits or absors electromagnetic radiation, but only in some frequencies that are characteristic of its chemical element.  

Now, if we supply energy in the form of heat (thermal energy) to a certain element in its gas phase, this will be stimulated and its atoms will emit radiation in certain frequencies of the visible spectrum, which constitute its <u>emission spectrum</u>.  

If the same element, also in gaseous state, receives electromagnetic radiation, it absorbs in certain frequencies of the visible spectrum, <u>precisely the same ones in which it emits when it is stimulated by heat</u>. This will be its <u>absorption spectrum.</u>  

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3 0
4 years ago
If a liter of water is heated from 20c to 50c what happens to its colume
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3 years ago
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andrezito [222]

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The right approach will be Option C "Group 12".

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Some other options in question are not relevant to something like the given scenario. Because then the option here is just the right one.

6 0
3 years ago
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