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VMariaS [17]
3 years ago
11

How do you write 3 3/5 as a percent?

Mathematics
2 answers:
elena-s [515]3 years ago
7 0
So first convert it it a mixed number so you get 18/10 next multiply by 100 to get 180%
dezoksy [38]3 years ago
6 0
5 x 20 =100 multiply the top and bottom of the fraction by 20 now we get 60%
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PLEASE HELP! THANKS!!
stepladder [879]
X=12 because I said so and I’m smart
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If the length of a netball court is 30.5m what scale has been used on this diagram?
aleksklad [387]
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3 years ago
Find the total mass of the triangular region shown below. All lengths are in cm, and the density of the region is sigma(x) = 1 +
anastassius [24]

Answer:

3 grams

Step-by-step explanation:

We are going to take the mass of a bunch of little strips below the triangle "roof." To do this, we must figure out what formula for the mass we'll use, in this case, we'll use:

Mass of strip = denisty * area = (1+x)*y*deltax grams

now, because the "roof" of the triangle contains two different integrals (it completely changes direction), we will use TWO integrals!

**pretend ∈ is the sum symbol

Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral -1 to 0 of (1+x)*3*(x+1) = 3 * integral -1 to 0 of (x^2 + 2x + 1) = 3 *  1/3 = 1

Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral 0 to 1 of (1+x)*3*(-x+1) = 3 * integral 0 to 1 of (-x^2 + 1) = 3 * 2/3 = 2

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8 0
3 years ago
What is the equation of the horizontal asymptote? f(x)=4(52)x+7<br> y=?
natta225 [31]

ANSWER

y=7

EXPLANATION

The horizontal asymptote of an exponential function

f(x)= a {(b)}^{x}  + c

is y=c.

The given exponential function is

f(x)= 4 {(52)}^{x}  + 7

When we compare to

f(x)= a {(b)}^{x}  + c

c=7, therefore the horizontal asymptote is y=7.

4 0
3 years ago
Use intercepts to graph the line described by each equation. -6y=-4x+24
Aloiza [94]
First, you have to get the equation to the normal form of a line. To do this, you divide both sides by -6 to get \frac{2}{3} x-4. The y-intercept is at -4 and your slope is 2/3. Use this to graph the equation.
3 0
3 years ago
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