Find the area of a rectangle with a length of 3 feet and a width of 2 7/8 feet.

The length of a cell phone is 1.41.4 inches and the width is 4.44.4 inches. The company making the cell phone wants to make a ne

4vir4ik [10]

Answer:

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Step-by-step explanation:

swhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhq

7 0

2 years ago

Name two pairs of adjacent angles and two pairs of vertical angles in the figure

insens350 [35]

Adjacent angles :

IGJ and IGH

KGL and LGM

vertical angles :

JGK and HGM

IGJ and MGL

hope this helps

7 0

2 years ago

Is 0.71428571428 a rational number

Alex787 [66]

No, since it a repeating(terminating) decimal, so it is not a rational number.

5 0

3 years ago

Read 2 more answers

A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marin

Tanya [424]

Let the coordinates of the treasure be (x,y).
Let $d_{1}$ = distance from the rock to the treasure.
Let $d_{2}$ = distance from the tree to the treasure.
$d_{1} = \sqrt{(x\2 + (y-2)^2}$
$d_{2} = \sqrt{(16-x)^2 + (21-y)^2}$
We want $\frac{ d_{1} }{ d_{2} }$ = 5/9 in order to locate the treasure.

Note that 5/9 = 0.556 (approx)
Test (11.4, 14.2)
d1 = 14.8, d2 = 8.2, d1/d2 = 1.8 Incorrect
Test (7.6, 8.8)
d1 = 8.2, d2 = 14.8, d1/d2 = 0.554 Correct
Test (5.7, 7.5)
d1 = 6.13, d2 = 16.98, d1/d2 = 0.36 Incorrect
Test (10.2, 12.6)
d1 = 12.8, d2 = 10.2, d1/d2 = 1.255 Incorrect

Answer: The correct answer is (7.6, 8.8)

4 0

2 years ago

Read 2 more answers

An elevator is rated to safely hold ten 250 lb people. The elevator is loaded as follows: three 600 lbs cartons of books, Jim (1

iris [78.8K]

To do this, we will need to find how much the elevator can hold in all. Multiply 10 by 250 to get 2500. Since it can also hold 10% more, multiply 2500 and 0.10 to find out how much 10% is. You get 250. Add 2500 and 250 to get how much the elevator can safely hold. It would be 2750.

To find out how much more weight can be added, first find out how much weight is on the elevator collectively. (books) 600+ (Jim) 180+ (Gavin) 330 + (Deb) 250 + (Susan) 120 = 1480. Subtract this from the amount the elevator can hold, and you get how much more weight can be added. 2750-1480= 1270.

The elevator can hold 1270 more ibs.

6 0

3 years ago

Read 2 more answers