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stellarik [79]
3 years ago
14

Consider the given function and the given interval. f\(x\) = 2 sin\(x\) - sin\(2 x\) text(, ) [0 text(, ) pi] (a) Find the avera

ge value fave of f on the given interval. fave = Correct: Your answer is correct. (b) Find c such that fave = f(c). (Enter solutions from smallest to largest. If there are any unused answer boxes, enter NONE in the last boxes. Round the answers to three decimal places.)
Mathematics
1 answer:
Finger [1]3 years ago
4 0

a. The average value of f on the given interval is

\displaystyle f_{\rm ave}=\frac1{\pi-0}\int_0^\pi(2\sin x-\sin2x)\,\mathrm dx=\boxed{\frac4\pi}

b. Solve for c:

\dfrac4\pi=2\sin c-\sin2c\implies\boxed{c\approx1.238\text{ or }c\approx2.808}

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frosja888 [35]
I have a feeling I've seen this question before
anyway

A=number of hours that plan A is
B=number of hours that plan B is

so

on wednesday, 7hr
5A and 6B so
5A+6B=7

on thursday, 3 hours
3 of A and 2  of B
3A+2B=3


so we gots

5A+6B=7
3A+2B=3

elimination
eliminate B's
multiply 2nd equation by -3 and add to 1st equation

5A+6B=7
<u>-9A-6B=-9 +</u>
-4A+0B=-2

-4A=-2
divide both sides by -4
A=1/2
A=0.5

sub back

3A+2B=3
3(0.5)+2B=3
1.5+2B=3
minus 1.5 both sides
2B=1.5
divide by 2 both sides
B=0.75


plan A lasts 1/2 hour or 0.5 hour or 30 mins
plan B lasts 3/4 hour or 0.75 hour or 45 mins
8 0
3 years ago
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The ratio of boys to girls in history class is 4to5 how many girls are in class if there are 12 boys in the class
DENIUS [597]
The answer is 15 girls
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The formula for the area of a triangle is A = 1bh. Solve the formula for h. If the
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Answer: H = 8 cm

Step-by-step explanation: Since a triangle's area is b times h/2, we know that two times 48 is 96, therefore we can opposite the equation so 12 is the base times the height (8 cm) is 96 divided by 2, there's your answer.

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I need help with this paper
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What grade is this?..

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What is the equation in point slope form of the line passing through (0,5) and (-2,11)
IRISSAK [1]

The equation of the line passing through (x_1,y_1) and (x_2,y_2) is

\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}. Here

\frac{y_2-y_1}{x_2-x_1} is the slope of the line.

Substituting numerical values, the equation of the line is

\frac{x-0}{y-5} =\frac{-2-0}{11-5} \\ \frac{x}{y-5} =-\frac{1}{3} \\ 3x=5-y\\ 3x+y=5

The equation of the line is 3x+y=5

6 0
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